问题
I have an existing table with records in it and I've just added a new column ver
which I would like to be unique.
create table foo (
bar text,
ver integer
);
select * from foo;
bar ver
--- ---
one null
two null
three null
I'm struggling with how to do this for some reason.
I want to do something like:
update foo set ver = ( select generate_series(1, 1000) );
or maybe
update foo set ver = v from (select generate_series(1, 1000) as v );
...but of course neither of those work. Can anyone point out the obvious for me?
回答1:
You need a primary key (or a unique column) to individually update rows of a table. In the lack of such a column you can use the hidden column ctid
which is unique by definition, example:
update foo f
set ver = rn
from (
select ctid, row_number() over (order by ctid) as rn
from foo
) s
where f.ctid = s.ctid
回答2:
Use some PL/pgSQL code:
DO
$$DECLARE
c CURSOR FOR SELECT * FROM foo;
x foo;
i integer := 1;
BEGIN
OPEN c;
LOOP
FETCH c INTO x;
EXIT WHEN NOT FOUND;
UPDATE foo SET ver = i WHERE CURRENT OF c;
i := i + 1;
END LOOP;
END;$$;
Then you can add a unique constraint:
ALTER TABLE foo ADD UNIQUE(ver);
回答3:
First, create a sequence.
create sequence foo_ver;
then add the column with a default value of the next number in the sequence.
alter table foo add ver integer default nextval('foo_ver') not null;
data is auto-populated, and new records will automatically get a new, unique number.
Optional: create unique index to be sure.
create unique index on foo(ver);
来源:https://stackoverflow.com/questions/46647848/updating-existing-records-with-a-unique-integer