问题
This is my code.
// insert reward into wallet
$sql = "
INSERT INTO `wallet` (`uid`, `created_at`, `amount`, `type`, `payment_id`) VALUES (:uid, CURRENT_TIMESTAMP, :amount, 'payment', :payment_id);
";
$sth = self::link()->prepare($sql);
// primary key makes sure payment does not get double rewarded
$sth->execute(
array(
':uid' => $referer,
':amount' => $reward,
':payment_id' => $payment_data['payment_id'],
)
);
var_dump(self::link()->errorInfo());
self::log("issuing subscription",self::LOG_LEVEL_DEBUG);
// extend referers subscription
$tid = self::link()->lastInsertId();
var_dump(self::link()->errorInfo());
self::log("using $tid as id for wallet transfer",self::LOG_LEVEL_DEBUG);
My log says:
[2011-07-02 20:31:44] using 0 as id for wallet transfer
However the insert query is successful, the database record is created and both errorInfo outputs give no error.
回答1:
Remove the semicolon or the whitespace after the semicolon or both from your query:
$sql = "
INSERT INTO `wallet` (`uid`, `created_at`, `amount`, `type`, `payment_id`) VALUES (:uid, CURRENT_TIMESTAMP, :amount, 'payment', :payment_id)
";
来源:https://stackoverflow.com/questions/6558885/why-does-pdolastinsertid-return-0