How to get background-image from inline css using selenium

问题

Using python how can I get the background image using selenium? Which has an inline CSS? I want to get the image URL from the background-image: url()

<div id="pic" class="pic" data-type="image" style=" background-image: url(http://test.com/images/image.png;); height: 306px; background-size: cover;"></div>

回答1:

To get the background image you need to use value_of_css_property(property_name) method and you have to induce WebDriverWait for the visibility_of_element_located() and you can use either of the following Locator Strategies:

• Using CSS_SELECTOR:

  import re
  
  my_property = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "div.pic#pic[data-type='image']"))).value_of_css_property("background-image")
  print(re.split('[()]',my_property)[1])
  

• Using XPATH:

  import re
  
  my_property = WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='pic' and @id='pic'][@data-type='image']"))).value_of_css_property("background-image")
  print(re.split('[()]',my_property)[1])
  

• Console Output:

  test.com/images/image.png
  

---

Update

As the url is getting wrapped up with in double quotes i.e. "..." you can use the following solution:

print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.XPATH, "//div[@class='pic' and @id='pic'][@data-type='image']"))).value_of_css_property("background-image").split('"')[1])

---

References

You can find a couple relevant discussions related to:

• Retrieving the background in How to convert #ffffff to #fff or #fff to #ffffff while asserting the background color rgb(255,255,255) returned by Selenium getCssValue("background")
• Retrieving a sub-string in How to retrieve a sub-string from a string that changes dynamically with respect to multiple delimiters through Selenium in Python

回答2:

Try This:

print(WebDriverWait(driver, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "div.pic#pic[data-type='image']"))).get_attribute("href"))

回答3:

To get the URL You need to use regular expression. In order to use regular expression Import re and then use the following regular expression.

import re
itemimage=WebDriverWait(driver, 20).until(EC.presence_of_element_located((By.CSS_SELECTOR, "div#pic"))).value_of_css_property("background-image")
print(re.search("(?P<url>http?://[^\s;]+)", itemimage).group("url")) 

Output:

http://test.com/images/image.png

来源：https://stackoverflow.com/questions/59103063/how-to-get-background-image-from-inline-css-using-selenium