问题
I want to do a HTTP POST of the format as follows,
<?xml version="1.0" encoding="UTF-8" ?>
<authRequest>
<username>someusernamehere</username>
<password>somepasswordhere</password>
</authRequest>
I usually work with the following mechanism for any login based POST,
HttpParams params = new BasicHttpParams();
params.setParameter(
"http.useragent",
"Mozilla/5.0 (Windows; U; Windows NT 6.1; en-GB; rv:1.9.2) Gecko/20100115 Firefox/3.6");
DefaultHttpClient httpclient = new DefaultHttpClient(params);
HttpPost httppost = new HttpPost("http://mysite.com/login");
List<NameValuePair> formparams = new ArrayList<NameValuePair>();
formparams.add(new BasicNameValuePair("username", "stackoverflow"));
formparams.add(new BasicNameValuePair("password", "12345"));
UrlEncodedFormEntity entity = new UrlEncodedFormEntity(formparams, "UTF-8");
httppost.setEntity(entity);
HttpResponse httpresponse = httpclient.execute(httppost);
But with this way, the POST data will be look like,
username=stackoverflow&password=12345
How can I format this request as per the specified XML format that I mentioned above?
Thanks in advance.
回答1:
Use a different kind of HttpEntity
. There are a number of implementations listed at the top of the documentation.
来源:https://stackoverflow.com/questions/9848557/how-to-send-xml-post-request-using-apache-httpclient