问题
I have the following code:
#include <iostream>
#include <boost\lexical_cast.hpp>
struct vec2_t
{
float x;
float y;
};
std::istream& operator>>(std::istream& istream, vec2_t& v)
{
istream >> v.x >> v.y;
return istream;
}
int main()
{
auto v = boost::lexical_cast<vec2_t>("1231.2 152.9");
std::cout << v.x << " " << v.y;
return 0;
}
I am receiving the following compile error from Boost:
Error 1 error C2338: Target type is neither std::istream
able nor std::wistream
able
This seems straightforward enough, and I have been hitting my head against the desk for the last hour. Any help would be appreciated!
EDIT: I am using Visual Studio 2013.
回答1:
There's 2-phase lookup at play.
You need to enable the overload using ADL, so lexical_cast
will find it in the second phase.
So, you should move the overload into namespace mandala
Here's a completely fixed example (you should also use std::skipws
):
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#include <iostream>
#include <boost/lexical_cast.hpp>
namespace mandala
{
struct vec2_t {
float x,y;
};
}
namespace mandala
{
std::istream& operator>>(std::istream& istream, vec2_t& v) {
return istream >> std::skipws >> v.x >> v.y;
}
}
int main()
{
auto v = boost::lexical_cast<mandala::vec2_t>("123.1 15.2");
std::cout << "Parsed: " << v.x << ", " << v.y << "\n";
}
来源:https://stackoverflow.com/questions/26989803/boostlexical-cast-not-recognizing-overloaded-istream-operator