问题
I have a third-party C library that defines a struct similar to:
struct myStruct {
int a;
int b;
char str1[32];
char str2[32];
};
And a function that takes a pointer to this struct and populates it. I need my Perl6 native call to provide that struct, and then read the results.
So far I've got the struct defined in Perl6 as:
class myStruct is repr('CStruct') {
has int32 $.a;
has int32 $.b;
has Str $.str1; # Option A: This won't work as Perl won't know what length to allocate
has CArray[uint8] $.str2; # Option B: This makes more sense, but again how to define length?
# Also, would this allocate the array in place, or
# reference an array that is separately allocated (and therefore not valid)?
}
And a native call like:
sub fillStruct(myStruct) is native('test_lib') { ... } my $struct = myStruct.new(); fillStruct($struct); # Gives a seg fault with any variation I've tried so far
How can I make this work?
回答1:
As others have said, there does not appear to be any way to achieve this at present.
I've resorted to defining a new C function(s) as a workaround. The function effectively acts as an accessor method returning just the fields that I need as discrete NativeCall-friendly pointers.
Hopefully the community will get to implementing proper support for this case at some point.
回答2:
At the time of writing, this doesn't seem to be handled.
As a workaround, my take would be to let a macro generate 32 int8
, adequately placing field names.
来源:https://stackoverflow.com/questions/46481221/how-to-define-fixed-length-strings-in-a-perl6-nativecall-struct