How to create a datetime object with PyYAML

问题

I'd like to be able to create a datetime object with datetime.datetime.now() PyYAML. It's easy to call some functions:

>>> y = """#YAML
... description: Something
... ts: !!python/object/apply:time.time []"""
>>> yaml.load(y)
{'description': 'Something', 'ts': 1289955567.940973}
>>>

However, I can't seem to figure out how to get a datetime.now(). I've tried as many permutations with calls to that using the various python yaml tags.

These all fail:

tests = [ 
        'dt: !!python/object:datetime.datetime.now []',
        'dt: !!python/object/new:datetime.datetime.now []',
        'dt: !!python/object/apply:datetime.datetime.now []',
]

for y in tests:
    try:
        print yaml.load(y)
    except Exception, err:
        print '==>', err

回答1:

I think this example achieves what you're looking for:

dt = yaml.load("""dt: !!python/object/apply:apply
    - !!python/object/apply:getattr
        - !!python/name:datetime.datetime
        - now
    - []
""")

However, I think it is too far-fetched because the !!python/object syntax supported by PyYAML is not supposed to call class methods (datetime.datetime.now is actually like a "static" factory method for datetime objects). As you said, this is simpler (though not what you're looking for):

dt = yaml.load("dt: !!python/object/apply:time.gmtime []")
dt = yaml.load("dt: !!python/object/apply:time.time []")

Another possible work-around would be to create a custom helper function that wraps the call to datetime.datetime.now so that it is easily serialized with !!python/object/apply. The cons is that this serialization would not be portable to an environment where this custom function is not found.

Anyway, in my opinion it does not make too much sense to serialize a value that always returns the current datetime (which would actually be the time when the YAML was parsed). PyYAML provides this shortcut for serializing a certain timestamp:

dt = yaml.load("""dt: !!timestamp '2010-11-17 13:12:11'""")

回答2:

The problem is that the object doesn't have a method that PyYAML needs to automatically generate the YAML representation. Why not just do datetime.datetime.now().isoformat() and store that string instead?

Alternately, you could put the desired properties of the datetime object in a dictionary and load that.

If you want to store the isoformat string, simply put it into a string and dump it:

timestamp = datetime.datetime.now().isoformat()

When you read it back in, use the strptime() method:

new_dt_object = datetime.datetime.strptime(timestamp, '%Y-%m-%dT%H:%M:%S.%f')

Of course, hilariously, I've just realized that you can just do:

yaml_timestamp = yaml.dump({'timestamp': datetime.datetime.now()})

If you load that with yaml.load(yaml_timestamp), you'll find yourself in possession of a shiny new datetime.datetime object.

来源：https://stackoverflow.com/questions/4200627/how-to-create-a-datetime-object-with-pyyaml

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python

YAML

pyyaml