Extract ZipFile using Python, display Progress Percentage?

问题

I know how to extract a zip archive using Python, but how exactly do I display the progress of that extraction in a percentage?

回答1:

the extract method doesn't provide a call back for this so one would have to use getinfo to get the e uncompressed size and then open the file read from it in blocks and write it to the place you want the file to go and update the percentage one would also have to restore the mtime if that is wanted an example:

import zipfile
z = zipfile.ZipFile(some_source)
entry_info = z.getinfo(entry_name)
i = z.open(entry_name)
o = open(target_name, 'w')
offset = 0
while True:
    b = i.read(block_size)
    offset += len(b)
    set_percentage(float(offset)/float(entry_info.file_size) * 100.)
    if b == '':
        break
    o.write(b)
i.close()
o.close()
set_attributes_from(entry_info)

this extracts entry_name to target_name

---

most of this is also done by shutil.copyfileobj but it doesn't have a call back for progress either

the source of the ZipFile.extract method calls _extract_member uses:

source = self.open(member, pwd=pwd)
target = file(targetpath, "wb")
shutil.copyfileobj(source, target)
source.close()
target.close()

where member has be converted from a name to a ZipInfo object by getinfo(member) if it wasn't a ZipInfo object

回答2:

I suggest using tqdm, it's super easy, like so:

>>> with zipfile.ZipFile(some_source) as zf:
...     for member in tqdm(zf.infolist(), desc='Extracting '):
...         try:
...             zf.extract(member, target_path)
...         except zipfile.error as e:
...             pass

This will produce something like so:

Extracting : 100%|██████████| 60.0k/60.0k [14:56<00:00, 66.9File/s]

来源：https://stackoverflow.com/questions/4341584/extract-zipfile-using-python-display-progress-percentage