问题
There is no error during auto-boxing of constants with int
and short
types to Byte
, but constant with long
type do has error. Why?
final int i = 3;
Byte b = i; // no error
final short s = 3;
Byte b = s; // no error
final long l = 3;
Byte b = l; // error
回答1:
From JLS Sec 5.2, "Assignment contexts" (emphasis mine):
In addition, if the expression is a constant expression (§15.28) of type byte, short, char, or int:
- A narrowing primitive conversion may be used if the type of the variable is byte, short, or char, and the value of the constant expression is representable in the type of the variable.
A narrowing primitive conversion followed by a boxing conversion may be used if the type of the variable is:
- Byte and the value of the constant expression is representable in the type byte.
- ...
It's simply not allowed for long
s by the spec.
Note that the second bullet point here says that this happens irrespective of the boxing: assigning a constant long
expression to a byte
variable would similarly fail:
// Both compiler errors.
byte primitive = 0L;
Byte wrapped = 0L;
来源:https://stackoverflow.com/questions/46206288/why-during-autoboxing-final-long-to-byte-compilation-error-happens-but-final-in