How to detect if building with address sanitizer when building with gcc 4.8?

问题

I'm working on a program written in C that I occasionally build with address sanitizer, basically to catch bugs. The program prints a banner in the logs when it starts up with info such as: who built it, the branch it was built on, compiler etc. I was thinking it would be nice to also spell out if the binary was built using address sanitizer. I know there's __has_feature(address_sanitizer), but that only works for clang. I tried the following simple program:

#include <stdio.h>

int main()
{
#if defined(__has_feature)
# if __has_feature(address_sanitizer)
    printf ("We has ASAN!\n");
# else
    printf ("We have has_feature, no ASAN!\n");
# endif
#else
    printf ("We got nothing!\n");
#endif

    return 0;
}

When building with gcc -Wall -g -fsanitize=address -o asan asan.c, this yields:

We got nothing!

With clang -Wall -g -fsanitize=address -o asan asan.c I get:

We has ASAN!

Is there a gcc equivalent to __has_feature?

I know there are ways to check, like the huge VSZ value for programs built with address sanitizer, just wondering if there's a compile-time define or something.

回答1:

From the GCC 4.8.0 manual:

__SANITIZE_ADDRESS__

This macro is defined, with value 1, when -fsanitize=address is in use.

来源：https://stackoverflow.com/questions/34813412/how-to-detect-if-building-with-address-sanitizer-when-building-with-gcc-4-8