问题
In Python, prefixing with one underscore indicates that a member should not be accessed outside of its class. This seems to be on a per-class basis like Java and C++.
However, pylint seems to enforce this convention on a per-object basis. Is there a way to allow per-class access without resorting to #pylint: disable=protected-access
?
class A:
def __init__(self):
self._b = 5
def __eq__(self, other):
return self._b == other._b
Result:
pylint a.py
a.py:6: W0212(protected-access) Access to a protected member _b of a client class
Pylint describes the message here.
回答1:
pylint doesn't know of which type other
is (how should it, you can compare an instance of A to everything), therefore the warning. I don't think there is a way around disabling the warning.
You can disable the warning for only that one line with appending # pylint: disable=W0212
to that line.
回答2:
Christian Geier is right about why you're getting the error, and how to disable it.
I'd encourage you to consider changing your code, though: pylint is telling you something important. From your example code looks like you want to use eq compare objects of class A to other objects of class A, but your example won't guarantee that a caller won't try A() == C()
. Returning True
when you check Circle()._radius == Sphere._radius
seems likely to cause problems.
See this stackoverflow thread for discussion of how to handle this.
来源:https://stackoverflow.com/questions/35701624/pylint-w0212-protected-access