Using StringTokenizer in Coverting words to number

问题

Can anyone please help me on how to convert words into numbers in Java programming, using string tokenizer. Your answer will be highly appreciated.

EDITED : I already made this code . but there is an error . like when i input one thousand one hundred , the program outputs 100100 . need your help guys . what do you think is the problem with my program and also what should i do . thanks alot ..

    import javax.swing.*;
         import java.util.*;
         import java.text.*;
         public class convertwordstonumbers {
         public static void main(String[] args) {

         String sInput;
         sInput=JOptionPane.showInputDialog("Enter a word/s:");
         StringTokenizer sToken= new StringTokenizer(sInput);
         int Tokens=sToken.countTokens();
         String Words[]=new String[Tokens];
         double Numbers[]=new double[Tokens];
         double Multiplier[]=new double[Tokens];
         String Place[]=new String[Tokens];
         int a=0;
         while(sToken.hasMoreTokens())
         {
        Words[a]=sToken.nextToken();
        a++;
        }
        String sUnits[]={"zero","one","two","three","four","five","six","seven","eight","nine"};
        String sTeens[]=   {"ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};
        String   sTys[]={"twenty","thirty","fourty","fifty","sixty","seventy","eighty","ninety"};
        String  sIons[]={"hundred","thousand","million","billion"};
        String   sThs[]={"tenths","hundredths"};
        double iUnits[]={0,1,2,3,4,5,6,7,8,9};
        double iTeens[]={10,11,12,13,14,15,16,17,18,19};
        double   iTys[]={20,30,40,50,60,70,80,90};
        double  iIons[]={100,1000,1000000,1000000000};
        double  iDecs[]={0.1,0.01};
        double iSum=0;
        for(int b=0;b<Tokens;b++){
        for(int c=0;c<10;c++){
            if(Words[b].compareToIgnoreCase(sUnits[c])==0){
                Numbers[b]=iUnits[c];
                Place[b]="a";
            }
        }
        for(int c=0;c<10;c++){
            if(Words[b].compareToIgnoreCase(sTeens[c])==0){
                Numbers[b]=iTeens[c];
                Place[b]="a";
            }
        }
        for(int c=0;c<8;c++){
            if(Words[b].compareToIgnoreCase(sTys[c])==0){
                Numbers[b]=iTys[c];
                Place[b]="a";
            }
        }
        for(int c=0;c<4;c++){
            if(Words[b].compareToIgnoreCase(sIons[c])==0){
                Numbers[b]=iIons[c];
                Place[b]="b";
                Multiplier[b]=iIons[c];
            }
        }
        for(int c=0;c<2;c++){
            if(Words[b].compareToIgnoreCase(sThs[c])==0){
                Numbers[b]=iDecs[c];
                Place[b]="b";
            }
        }
    }
        for(int d=0;d<Tokens;d++){
        if(Place[d]==null){
            JOptionPane.showMessageDialog(null, "Invalid input");
            System.exit(0);
        }
        if(Place[d]=="a")
            iSum+=Numbers[d];
        if(Place[d]=="b")
            iSum*=Numbers[d];
    }
   if (iSum<1000)
    {DecimalFormat dFormat= new DecimalFormat("0.00");
    System.out.println(dFormat.format(iSum));}
         else 
         {DecimalFormat dFormat= new DecimalFormat("0,000.00");
         System.out.println(dFormat.format(iSum));
            }
    }``
}

回答1:

I think stringtokenizer is not enough, you need a dictionary to transalate from your language to number

see also http://nlp.stanford.edu/nlp/javadoc/javanlp/edu/stanford/nlp/ie/NumberNormalizer.html

Provides functions for converting words to numbers Unlike QuantifiableEntityNormalizer that normalizes various types of quantifiable entities like money and dates, NumberNormalizer only normalizes numeric expressions (e.g. one => 1, two hundred => 200.0 )

回答2:

The StringTokenizer has a constructor that allows specific delimiters. Assuming you wish to delimit each token by a mere space " " you could use a ArrayList with each token pre-specifically placed using numbers 0-9.

 ArrayList<String> token;

 token.add("zero");
 token.add("one"); ... etc

 StringTokenizer s = new StringTokenizer("four zero four", " ");
 String num_rep = token.indexOf(s.nextToken()) + token.indexOf(s.nextToken()) + token.indexOf(s.nextToken());

回答3:

You need to write a logic for comparing the string with standard words, and then building the number on the go.

Just an observation: StackOverflow is not a place to get your assignments solved.

来源：https://stackoverflow.com/questions/21145754/using-stringtokenizer-in-coverting-words-to-number

标签

java

stringtokenizer