问题
For this code:
int i;
scanf("%d\n",&i);
I am not able to stop my program until I input two numbers.
I think it is very strange ,I know when the input is suitable,the scanf will return 1. When I input "12a 'Enter'","12 'Enter'2" and so on ,it is ok,the i=12,it seems that when I input something is different int or input a 'Enter' and something another,the scanf returns 1.
What am I missing?
回答1:
"I am not able to stop my program until I input two numbers when I use scanf("%d\n",&i);"
Although this format makes scanf read the number and store it into i, this "reading" continues and it lasts till non-whitespace character followed by \n is found. This is the reason why input 1 2 makes this scanf stop.
You should not specify newline in the input format in this case.
Use scanf("%d",&i); instead.
回答2:
It's because of the '\n in the scanf...
If you want to move into a new line, just put :
printf ("\n");
and it'll give u an empty line...
回答3:
scanf("%d\n",&i);
read the number till non-whitespace character appear(ignore all whitespace and '\n' after the number).
来源：https://stackoverflow.com/questions/9516192/problems-with-scanfd-n-i