问题
First of all I apologize for my poor english which is not my first language.
I'm new in MVVM so my question is probably a very newbie one ;)
I'm encountering some issue with switching View in a C# Application using WPF and MVVM LIGHT. I've read a lot of articles but i still can't figured out how to do it in a clean way.
So here is my question: What is the best way to achieve the navigation between UserControl contained in a MainWindows, assuming that:
- I've a ViewModel for each UserControl and one for the Main Windows.
- The buttons for switching between usercontrols are contained into UserControl itself
- I've a ViewModelLocator
- I need to sometimes Destroy/re-create a userControl's ViewModel
- I want to respect the MVVM Pattern.
- I want to keep it simple
回答1:
Since nobody answers to my question, this is what I finally did. It might not be the best way but at least it works well. I hope it'll helps some newbies like me who are struggling learning this pattern:
Put a CurrentViewModel Object in the MainViewModel:
public class MainViewModel : ViewModelBase,IMainViewModel
{
/* Other piece of code */
private ViewModelBase _currentViewModel;
public ViewModelBase CurrentViewModel
{
get
{
return _currentViewModel;
}
set
{
_currentViewModel = value;
RaisePropertyChanged(() => CurrentViewModel);
}
}
}
Obviously bind this to the Mainview (Just the relevant code):
<UserControl Content="{Binding Path=CurrentViewModel}"/>
Put the DataTemplate in the App.xaml:
<Application.Resources>
<ResourceDictionary>
<vm:ViewModelLocator x:Key="Locator" d:IsDataSource="True" />
<DataTemplate DataType="{x:Type localViewModel:HomeViewModel }">
<localView:AccueilView/>
</DataTemplate>
<DataTemplate DataType="{x:Type localViewModel:ErrorViewModel }">
<localView:ErrorView/>
</DataTemplate>
</ResourceDictionary>
</Application.Resources>
Register the ViewModel with Simple IOC in the ViewModelLocator:
if (ViewModelBase.IsInDesignModeStatic)
{
SimpleIoc.Default.Register<IHomeViewModel, DesignHomeViewModel>();
}
else
{
SimpleIoc.Default.Register<IHomeViewModel, HomeViewModel>();
}
Set the getter of all the ViewModel in the ViewModelLocator to Static (just one for the exemple)
public static IHomeViewModel Home
{
get{return ServiceLocator.Current.GetInstance<IHomeViewModel>();}
}
Since it's static you can access the ViewModel you want from the MainViewModel:
public class MainViewModel : ViewModelBase,IMainViewModel
{
public ViewModelBase HomeVM
{
get
{
return (ViewModelBase)ViewModelLocator.Home;
}
}
}
Provide the ability to unregister the ViewModel and recreates it:
public static void CleanUpHome()
{
SimpleIoc.Default.Unregister<HomeViewModel>();
SimpleIoc.Default.Register<IHomeViewModel, HomeViewModel>();
}
The "child" View Model communicates with the MainViewModel through messages:
public class ErrorViewModel : ViewModelBase, IErrorViewModel
{
/*Other piece of code */
public void HomeReturn()
{
var msg = new ChangeView(ChangeView.EnumView.Home);
Messenger.Default.Send<ChangeView>(msg);
ViewModelLocator.CleanUpErrors();
}
}
The MainViewModel Register to the message and processes it:
public class MainViewModel : ViewModelBase,IMainViewModel
{
public MainViewModel()
{
Messenger.Default.Register<ChangeView>(this, (action) => ReceiveMessage(action));
CurrentViewModel = HomeVM;
}
private void ReceiveMessage(ChangeView viewName)
{
switch (viewName.switchView)
{
case ChangeView.EnumView.Home:
CurrentViewModel = HomeVM;
break;
case ChangeView.EnumView.Error:
CurrentViewModel = ErrorVM;
break;
}
Messenger.Default.Unregister<ChangeView>(this, (action) => ReceiveMessage(action));
}
That's all.
来源:https://stackoverflow.com/questions/35221894/navigate-through-usercontrol-with-mvvm-light-wpf