How to call (dialing) with “ * ” char in IOS?

问题

I hope to call with * character. ex> *711313.

Currently, I'm using this code:

NSString *str = [NSString stringWithFormat:@"tel:%@", tmp];

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:[str stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]];

I tested two cases:

1. tmp = @"719929292"; //this is ok. make call.

2. tmp = @"*7128282"; //app no reaction. not to call.

How can I call with *(star character)?

回答1:

The star may have to be encoded for use in a URL. Try %2A instead of *.

This replacement is not done by stringByAddingPercentEscapesUsingEncoding: since * is a valid URL character, albeit with a special meaning.

来源：https://stackoverflow.com/questions/12909631/how-to-call-dialing-with-char-in-ios