问题
I'm trying to parse an HTML document for a web indexing program. To do this I'm using HTML::TokeParser.
I'm getting an error on the last line of my first if statement:
if ( $token->[1] eq 'a' ) {
#href attribute of tag A
my $suffix = $token->[2]{href};
that says Can't use string ("<./a>") as a HASH ref while "strict refs" in use at ./indexer.pl line 270, <PAGE_DIR> line 1.
Is my problem that (the suffix? or <./a>
?) is a string and needs to be turned into a hash ref? I looked at other posts that had similar errors.. but I'm still not at all sure about this. Thanks for any help.
sub parse_document {
#passed from input
my $html_filename = $_[0];
#base url for links
my $base_url = $_[1];
#created to hold tokens
my @tokens = ();
#created for doc links
my @links = ();
#creates parser
my $p = HTML::TokeParser->new($html_filename);
#loops through doc tags
while (my $token = $p->get_token()) {
#code for retrieving links
if ( $token->[1] eq 'a' ) {
# href attribute of tag A
my $suffix = $token->[2]{href};
#if href exists & isn't an email link
if ( defined($suffix) && !($suffix =~ "^mailto:") ) {
#make the url absolute
my $new_url = make_absolute_url $base_url, $suffix;
#make sure it's of the http:// scheme
if ($new_url =~ "^http://"){
#normalize the url
my $new_normalized_url = normalize_url $new_url;
#add it to links array
push(@links, $new_normalized_url);
}
}
}
#code for text words
if ($token->[0] eq 'T') {
my $text = $token->[1];
#add words to end of array
#(split by non-letter chars)
my @words = split(/\P{L}+/, $text);
}
}
return (\@tokens, \@links);
}
回答1:
The get_token()
method returns an array where $token->[2]
is a hash reference containing your href
only if $token->[0]
is an S (that is, a start tag). In this case, you are matching an end tag (where $token->[0]
is an E). See the PerlDoc for details.
To fix, add a
next if $token->[0] ne 'S';
at the top of your loop.
回答2:
$token->[2]
is a string, not a hash reference.
Do a print $token->[2]
and you'll see that it is a string containing </a>
回答3:
apparently $token->[2]
is resolving as a hash reference whose value is "</a>"
. Certainly not want you want!
来源:https://stackoverflow.com/questions/7958679/cant-use-string-as-a-hash-ref