问题
I'm building a simple website which uses mysql as backend. I have a form which has 2 buttons of which one searches data from db and populates the page using Ajax another button updates the new values to db. Now my problem is i can't use both buttons as 'Submit' button.
Ajax Method & Html Form:
<script type="text/javascript">
$(document).ready(function(){
$(document).on('submit', '#update-form', function(){
var data = $(this).serialize();
$.ajax({
type : 'POST',
url : 'search.php',
data : data,
success : function(data){
$(".display").html(data);
}
});
return false;
});
});
</script>
<body>
<div id="update" class="tab-pane fade">
<form id="update-form" role="form" class="container" method="post" action="search.php">
<h3>Update details</h3>
<table class="display">
<tr class="space">
<td><label>File Number:</label></td>
<td><input type="text" class="form-control" name="filenum" required></td>
</tr>
</table>
<button type="submit" class="btn btn-default text-center" name="search_btn" >Search</button>
<button type="submit" class="btn btn-default text-center" name="submit_btn" formaction="update.php">Update</button>
</form>
</div>
</body>
Now i want to know how can i modify above code so that i can use both button as submit.
Tried withformaction
but it doesn't work because of Ajax method usage.
回答1:
You can do this in many ways.
The first that come to my mind is: change the button type to be button instead of submit and add a onclick attribute
<button type="button" onclick="submitForm('search.php')">Search</button>
<button type="button" onclick="submitForm('update.php')">Update</button>
Then in your javascript:
function submitForm(url){
var data = $("$update-form").serialize();
$.ajax({
type : 'POST',
url : url,
data : data,
success : function(data){
$(".display").html(data);
}
});
}
回答2:
In jquery you can trigger a submit. Check this : https://api.jquery.com/submit/
You create a div or other and in jquery you add a listener to this div :
<div id="button">Here my button</div>
And in jquery
$('#button').on('click', function(){
$('#update-form').submit()
}
回答3:
<form id="update-form">
...
...
<button type="button" class="submitForm" formaction="search.php">Search</button>
<button type="button" class="submitForm" formaction="update.php">Update</button>
</form>
And then your JS:
$('.submitForm').click(function(){
$.ajax({
method: 'post',
url: $(this).attr('formaction),
data: $("#update-form").serialize(),
...
...
success: function(){ }
});
});
回答4:
$(document).ready(function(){
$(document).on('submit', '#update-form', function(){
var data = $(this).serialize();
$.ajax({
type : 'POST',
url : 'search.php',
data : data,
success : function(data){
$(".display").html(data);
}
});
return false;
});
$(document).on('click', '#update-btn', function(){
var data = $("input[name='filenum']").val(); //Handle how you want
$.ajax({
type : 'POST',
url : 'update.php',
data : data,
success : function(data){
$(".display").html(data);
}
});
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<body>
<div id="update" class="tab-pane fade">
<form id="update-form" role="form" class="container" method="post" action="search.php">
<h3>Update details</h3>
<table class="display">
<tr class="space">
<td><label>File Number:</label></td>
<td><input type="text" class="form-control" name="filenum" required></td>
</tr>
</table>
<button type="submit" class="btn btn-default text-center" name="search_btn" >Search</button>
<button form='forn-is-not-exist' class="btn btn-default text-center" name="submit_btn" id="update-btn" >Update</button>
</form>
</div>
</body>
Check it out
来源:https://stackoverflow.com/questions/39702648/how-to-use-multiple-submit-buttons-in-a-single-form-having-ajax