问题
I've tried using "FOR XML PATH", "FOR XML EXPLICIT" and "FOR XML AUTO" but the data is never structured with the correct heirarchy.
Basically, I have one parent table (Customers) and 3 child tables. Each table has a customerid column. There is a one-to-many relationship from the Customers table to each of the 3 child tables.
As a mock example, I have a parent "Customers" table, and I have 3 other tables - Products, Hobbies and Vehicles - all related to the Customers table by a customerid.
What is the SQL code to achieve the following kind of structure -
<Customers>
<Customer customerid="1" name="Fred">
<Products>
<Product productname="table" />
<Product productname="chair" />
<Product productname="wardrobe" />
</Products>
<Hobbies>
<Hobby hobbyname="Golf" />
<Hobby hobbyname="Swimming" />
</Hobbies>
<Vehicles>
<Vehicle name="Car" color="Red" />
<Vehicle name="Bicycle" color="Blue" />
</Vehicles>
</Customer>
<Customer customerid="2" name="Sue">
<Products>
<Product productname="CD player" />
<Product productname="Picture frame" />
</Products>
<Hobbies>
<Hobby hobbyname="Dancing" />
<Hobby hobbyname="Reading" />
</Hobbies>
<Vehicles>
<Vehicle name="Car" color="Yellow" />
</Vehicles>
</Customer>
</Customers>
回答1:
Try something like this - it uses FOR XML PATH and subselects to create the "linked" sub-nodes for a given customer (I limited this to two sub tables - but you should get the "gist" of it and be able to extend it to any number of linked subtables):
SELECT
CustomerID AS '@CustomerID',
CustName AS '@Name',
(SELECT ProductName AS '@productname'
FROM dbo.Products p
WHERE p.CustomerID = c.CustomerID
FOR XML PATH('Product'), TYPE) AS 'Products',
(SELECT HobbyName AS '@hobbyname'
FROM dbo.Hobbies h
WHERE h.CUstomerID = c.CustomerID
FOR XML PATH('Hobby'), TYPE) AS 'Hobbies'
FROM
dbo.Customers c
FOR XML PATH('Customer'), ROOT('Customers')
Gives me an output something like:
<Customers>
<Customer CustomerID="1" Name="Fred">
<Products>
<Product productname="Table" />
<Product productname="Wardrobe" />
<Product productname="Chair" />
</Products>
<Hobbies>
<Hobby hobbyname="Golf" />
<Hobby hobbyname="Swimming" />
</Hobbies>
</Customer>
<Customer CustomerID="2" Name="Sue">
<Products>
<Product productname="CD Player" />
<Product productname="Picture frame" />
</Products>
<Hobbies>
<Hobby hobbyname="Dancing" />
<Hobby hobbyname="Gardening" />
<Hobby hobbyname="Reading" />
</Hobbies>
</Customer>
</Customers>
回答2:
Using FOR XML RAW
IF OBJECT_ID ('tempdb..#customer') IS NOT NULL DROP TABLE #Customer
IF OBJECT_ID ('tempdb..#product') IS NOT NULL DROP TABLE #product
IF OBJECT_ID ('tempdb..#vehicle') IS NOT NULL DROP TABLE #Vehicle
IF OBJECT_ID ('tempdb..#hobbies') IS NOT NULL DROP TABLE #Hobbies
CREATE TABLE #Customer (id INT,name NVARCHAR(20))
INSERT INTO #customer SELECT 1,'Fred' UNION ALL SELECT 2,'Sue'
CREATE TABLE #product(customer_id INT, name NVARCHAR(20))
INSERT INTO #product
SELECt 1 AS id, 'table' as product
UNION ALL SELECT 1 AS id, 'chair' as product
UNION ALL SELECT 1 AS id, 'wardrobe' as product
UNION ALL SELECT 2 AS id, 'CD Player' as product
UNION ALL SELECT 2 AS id, 'Picture Frame' as product
CREATE TABLE #vehicle(customer_id INT, name NVARCHAR(20),colour NVARCHAR(20))
INSERT INTO #vehicle
SELECt 1 AS id, 'Car' as vehicle,'red' as colour
UNION ALL SELECT 1 AS id, 'bicycle' as vehicle,'Blue' AS colour
UNION ALL SELECT 2 AS id, 'Car' as vehicle, 'Yellow' as colour
CREATE TABLE #hobbies(customer_id INT, name NVARCHAR(20))
INSERT INTO #hobbies
SELECt 1 AS id, 'Golf' as name
UNION ALL SELECT 1 AS id, 'Swimming' as name
UNION ALL SELECT 2 AS id, 'Dancing' as name
UNION ALL SELECT 2 AS id, 'Reading' as name
SELECT
c.id AS id
,c.name AS name
,(SELECT p.name
FROM #product p
WHERE p.customer_id = c.id
FOR XML RAW('Products'),TYPE) AS Products
,(SELECT h.name
FROM #hobbies h
WHERE h.customer_id = c.id
FOR XML RAW('Hobbies'),TYPE) AS Hobbies
,(SELECT v.name,v.colour
FROM #vehicle v
WHERE v.customer_id = c.id
FOR XML RAW('Vehicle'),TYPE) AS Vehicle
FROM #customer c
FOR XML RAW('Customer'), ROOT('Customers')
回答3:
select
c.customerid,
c.name,
(
select p.productname
from Products as p
where p.customerid = c.customerid
for xml raw('Product'), root('Products'), type
),
(
select h.hobbyname
from Hobbies as h
where h.customerid = c.customerid
for xml raw('Hobby'), root('Hobbies'), type
),
(
select v.name, v.color
from Vehicles as v
where v.customerid = c.customerid
for xml raw('Vehicle'), root('Vehicles'), type
)
from Customers as c
for xml raw('Customer'), root('Customers')
=> sql fiddle demo
回答4:
DECLARE @sampleCount int =10
SET STATISTICS TIME ON
SELECT
(SELECT TOP (@sampleCount) * FROM [Table1]TABLESAMPLE(100 PERCENT) FOR XML PATH('tbl1'), TYPE) AS 'tbl1',
(SELECT top (@sampleCount) * FROM [Table2] TABLESAMPLE(100 PERCENT) FOR XML PATH('tbl2'), TYPE) AS 'tbl2',
(SELECT top (@sampleCount) * FROM [Table3] TABLESAMPLE(100 PERCENT) FOR XML PATH('tbl3'), TYPE) AS 'tbl3'
FOR XML PATH(''), ROOT('Table')
回答5:
USE [EAPP_BranchDb]
GO
/****** Object: StoredProcedure [dbo].[SP_procXMLOutput] Script Date: 09/05/2013 15:14:05 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE PROCEDURE [dbo].[SP_procXMLOutput]
@Data XML OUTPUT
AS
BEGIN
DECLARE @myDoc xml,
@myDoc1 xml,
@var_Doc1 nvarchar(max),
@myDoc2 xml,
@var1 nvarchar(max),
@var2 nvarchar(max),
@var3 nvarchar(max),
@var_id as int,
@var_id1 as nvarchar(10),
@var_grp_id1 as nvarchar(10),
@var_parent_id as bigint,
@var_grp_id as nvarchar(10),
@var_parent_type as nvarchar(1),
@var_type as nvarchar(10),
@xml XML,
@grp1 nvarchar(max),
@grp2 nvarchar(max)
DECLARE xml_cur_id CURSOR FOR
SELECT id, parent_id, grp_id, parent_type,type FROM xml_table where parent_type='P' order by id
DECLARE xml_cur_grpid CURSOR FOR
SELECT GRP_ID FROM xml_table WHERE parent_id=6 and parent_type='C' group by GRP_ID
BEGIN
SET @myDoc = N'<frameSet label="Personal Details" id="1"
</frameSet';
SET @var_Doc1='<field pid="6" type="ROW" /</field';
OPEN xml_cur_id
FETCH NEXT FROM xml_cur_id INTO @var_id, @var_parent_id, @var_grp_id, @var_parent_type,@var_type
WHILE @@FETCH_STATUS = 0
BEGIN
IF @var_type<'TABLE' and @var_parent_type='P'
BEGIN
SET @myDoc1=(SELECT id, name, type, isMandtory, isDependent, isDependentValue,dataType, lookupPath, lookupName, defaultValue, minDate, maxDate, fieldLabel, maxLength, readonly, disabled, onChangeEvent, reloadEvent, validationMessage, tabindex FROM xml_table WHERE id=@var_id FOR XML RAW('field'))
SET @myDoc.modify('insert sql:variable("@myDoc1") as last into (/frameSet)[1] ')
END
IF @var_type='TABLE' and @var_parent_type='P'
BEGIN
/*table parent creation START*/
SET @myDoc1=(SELECT id, name, type,fieldLabel FROM xml_table WHERE id=@var_id FOR XML RAW('field'))
SET @myDoc.modify('insert sql:variable("@myDoc1") as last into (/frameSet)[1] ')
/*table parent creation END*/
/*table COLUMN creation START*/
SELECT @var1=(SELECT type,fieldLabel FROM XML_RELATION_TABLE WHERE Parent_id=6 order by id FOR XML RAW('field'))
SELECT @var2=(SELECT '<field type="ROW"'+@var1+'</field')
SELECT @myDoc1=@var2
SET @var_id1=@var_id
/*table COLUMN creation START*/
/*TABLE CHILD row creation START*/
SET @var3=''
OPEN xml_cur_grpid
FETCH NEXT FROM xml_cur_grpid INTO @var_grp_id1
WHILE @@FETCH_STATUS = 0
BEGIN
SELECT @grp1=(SELECT id, name, type, isMandtory, isDependent, isDependentValue,dataType, lookupPath,
lookupName, defaultValue, minDate, maxDate, fieldLabel, maxLength,
readonly, disabled, onChangeEvent, reloadEvent, validationMessage, tabindex FROM xml_table
WHERE parent_id=@var_parent_id and parent_type='C' and grp_id=@var_grp_id1 order by id
FOR XML RAW('field'))
SELECT @grp2=(SELECT '<field type="ROW"'+@grp1+'</field')
SET @var3=@var3+@grp2
FETCH NEXT FROM xml_cur_grpid INTO @var_grp_id1
END
CLOSE xml_cur_grpid
DEALLOCATE xml_cur_grpid
/*TABLE CHILD row creation END*/
SELECT @myDoc1=@var2+@var3
SET @myDoc.modify('insert sql:variable("@myDoc1") into (/frameSet/field[@id=sql:variable("@var_id1")])[1] ')
SET @var2=''
SET @var3=''
END
FETCH NEXT FROM xml_cur_id INTO @var_id, @var_parent_id, @var_grp_id, @var_parent_type,@var_type
END
CLOSE xml_cur_id
DEALLOCATE xml_cur_id
SET @Data=@myDoc
END
END
GO
来源：https://stackoverflow.com/questions/11260156/how-to-return-xml-from-sql-server-2008-that-is-structured-with-multiple-selectio