How to get inserted id using Spring Jdbctemplate.update(String sql, obj…args)

和自甴很熟 提交于 2019-12-22 06:07:09

问题


I'm using Jdbctemplate and I need the inserted id of a query. I read that I have to build a particular PreparedStatement and use GeneratedKeyHolder object.

The problem is that in my application all inserts method uses this JdbcTemplate update method:

getJdbcTemplate().update(SQL_INSERT,param1,param2,param3,...);

Is there another way to get the inserted id without refactoring all daos?


回答1:


Looking at the documentation for NamedParameterJdbcTemplate and JdbcTemplate You have two choices:

use NamedParameterJdbcTemplate's update method.

use JdbcTemplate's update method.

There are also some other methods available which will populate the keys to the given GeneratedKeyHolder, it's up to you which one suits your needs.

EDIT

For e.g. using JdbcTemplate:

GeneratedKeyHolder holder = new GeneratedKeyHolder();
jdbcTemplate.update(new PreparedStatementCreator() {
    @Override
    public PreparedStatement createPreparedStatement(Connection con) throws SQLException {
        PreparedStatement statement = con.prepareStatement("INSERT INTO SOME_TABLE(NAME, VALUE) VALUES (?, ?) ", Statement.RETURN_GENERATED_KEYS);
        statement.setString(1, "SomeName");
        statement.setString(2, "SomeValue");
        return statement;
    }
}, holder);

long primaryKey = holder.getKey().longValue();


来源:https://stackoverflow.com/questions/35088885/how-to-get-inserted-id-using-spring-jdbctemplate-updatestring-sql-obj-args

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