LARAVEL UNIT TEST - Opposite of seeInDatabase

问题

In Laravel 5.1 there is a method that asset if some data are in database using the seeInDatabase($table,$fields)...

Is there a way to assert if the some data arent in database? Something like dontSeeInDatabase... Similiar to dontSeeJson

回答1:

Laravel v5.6

Assertion name has changed

->assertDatabaseMissing(string $table, array $data, string $connection = null) 

the opposite would be

->assertDatabaseHas(string $table, array $data, string $connection = null)

Previous Laravel versions

There are two ways:

->notSeeInDatabase($table, array $data)  

and

->missingFromDatabase($table, array $data)

One is just an alias for the other.

For a full list of available testing methods take a look at the traits located at vendor/laravel/framework/src/Illuminate/Foundation/Testing

回答2:

In recent versions of Laravel (5.4 as of now) , seeInDatabase and missingFromDatabase methods are not available. Instead, there are assertDatabaseHas and assertDatabaseMissing methods. Usage is the same:

->assertDatabaseHas($table, array $data)

->assertDatabaseMissing($table, array $data)

So, if you're using recent versions of Laravel as of now and doing testing, you should try assertDatabaseMissing().

来源：https://stackoverflow.com/questions/32355020/laravel-unit-test-opposite-of-seeindatabase