List with duplicated values and suffix

Question

I have a list, a:

a = ['a','b','c']

and need to duplicate some values with the suffix _ind added this way (order is important):

['a', 'a_ind', 'b', 'b_ind', 'c', 'c_ind']

I tried:

b = [[x, x + '_ind'] for x in a]
c = [item for sublist in b for item in sublist]
print (c)
['a', 'a_ind', 'b', 'b_ind', 'c', 'c_ind']

I think my solution is a bit over-complicated. Is there some better, more pythonic solution?

Answer 1

You could make it a generator:

def mygen(lst):
    for item in lst:
        yield item
        yield item + '_ind'

>>> a = ['a','b','c']
>>> list(mygen(a))
['a', 'a_ind', 'b', 'b_ind', 'c', 'c_ind']

You could also do it with itertools.product, itertools.starmap or itertools.chain or nested comprehensions but in most cases I would prefer a simple to understand, custom generator-function.

---

With python3.3, you can also use yield from—generator delegation—to make this elegant solution just a bit more concise:

def mygen(lst):
    for item in lst:
        yield from (item, item + '_ind')

Answer 2

It can be shortened a little bit by moving the options to the inner for loop in the list comprehension:

a = ['a','b','c']

[item for x in a for item in (x, x + '_ind')]
# ['a', 'a_ind', 'b', 'b_ind', 'c', 'c_ind']

Answer 3

Another alternative with splicing (Python2.x, 3.x):

In [642]: result = [None] * len(a) * 2

In [643]: result[::2], result[1::2] = a, map(lambda x: x + '_ind', a)

In [644]: result
Out[644]: ['a', 'a_ind', 'b', 'b_ind', 'c', 'c_ind']

Answer 4

You can use itertools.chain():

import itertools

l = ['a','b','c']

new_list = list(itertools.chain.from_iterable([[i, i+"_ind"] for i in l]))

print new_list

Output:

['a', 'a_ind', 'b', 'b_ind', 'c', 'c_ind']

Answer 5

Before list comprehensions and generators were invented/became widespread, people used to think much simpler¹:

>>> a = ['a', 'b', 'c']
>>> b = []
>>> for x in a: b.extend([x, x+'_ind'])
... 
>>> b
['a', 'a_ind', 'b', 'b_ind', 'c', 'c_ind']

---

^* I don't mean that those constructs/tools are evil, just wanted to point out that there is a simple solution.

Answer 6

Since you asked for "simple", I thought I'd throw this in (albeit, maybe not the pythonic way):

for i in mylist: 
    mylist1.append(i);
    mylist1.append(i + '_ind');