问题
Recently I found a piece of C++ code that effectively does the following:
char* pointer = ...;
const char* constPointer = const_cast<const char*>( pointer );
Obviously the author thought that const_cast
means "add const", but in fact const
can be just as well added implicitly:
const char* constPointer = pointer;
Is there any case when I would really have to const_cast
to a pointer-to-const (const_cast<const Type*>
as in above example)?
回答1:
const_cast
, despite its name, is not specific to const
; it works with cv-qualifiers which effectively comprises both const
and volatile
.
While adding such a qualifier is allowed transparently, removing any requires a const_cast
.
Therefore, in the example you give:
char* p = /**/;
char const* q = const_cast<char const*>(p);
the presence of the const_cast
is spurious (I personally think it obscures the syntax).
But you can wish to remove volatile
, in which case you'll need it:
char const volatile* p = /**/;
char const* q = const_cast<char const*>(p);
This could appear, for example, in driver code.
回答2:
Where you have 2 overloads and you want to force the const one to be executed. This is often the case when you call one in terms of the other.
class A
{
public:
B* get();
const B* get() const;
};
I have a non-const A but want to run get() const I might cast. In particular I might do this in the implementation of the non-const itself.
B* A::get()
{
return const_cast<B*>( const_cast< const A*>(this)->get() );
}
Of course we could do:
B* A::get()
{
const A* constthis = this; // no need to cast
return const_cast<B*>(constthis->get());
}
so we did not have to cast but it makes the first solution a one-liner and no need to create a temp variable.
回答3:
Maybe to force overload resolution in cases where you have f(T*) and f(const T*).
回答4:
You can use static_cast
to add const as well. So I don't see any situation where you have to use const_cast
to add const
. But explicit casting (be it one or another) can sometimes be needed when you want to change the type of the object for example for overload resolution.
E.g.
void f(char*);
void f(const char*);
int main()
{
char* p = 0;
f(p); //calls f(char*)
f(static_cast<const char*>(p)); //calls f(const char*);
f(const_cast<const char*>(p)); //calls f(const char*);
}
来源:https://stackoverflow.com/questions/5324256/is-const-castconst-type-ever-useful