问题
can someone explain me why code like this:
networApi.getList()
.subscribeOn(Schedulers.newThread())
.observeOn(AndroidSchedulers.mainThread())
.doOnError(throwable -> {
throwable.getMessage();
})
.doOnNext(list -> {
coursesView.populateRecyclerView(list);
courseList = (List<Course>) courses;
}).subscribe();
If there is no internet goes into doOnError but throws it further so the app goes down, but code like this:
networkApi.getList()
.subscribeOn(Schedulers.newThread())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(new Subscriber<List<? extends Course>>() {
@Override
public void onCompleted() {
}
@Override
public void onError(Throwable e) {
e.getMessage();
}
@Override
public void onNext(List<? extends Course> list) {
coursesView.populateRecyclerView(list);
courseList = (List<Course>) list;
}
});
Work how I expect, it means when there is no internet connection it does nothing.
回答1:
Basically, doOnError
does not handle the error, in the sense that it does not consume it. It just does something with it, log it, for example. (The same is true for doOnNext
- it also does not consume the item and the item still ends up in onNext
of the Subscriber
).
The error is still sent down the chain and would still end up in the onError
of your Subscriber
.
I am pretty certain that your app is crashing with an OnErrorNotImplementedException
and that is because you don't have any Subscriber
at all and therefore no onError
method.
来源:https://stackoverflow.com/questions/33670101/why-rxjava-with-retrofit-on-android-doonerror-does-not-work-but-subscriber-one