Recursively retrieve LAG() value of previous record

问题

I've made the following calculation involving LAG():

(lag(fValue,1,fValue) OVER (PARTITION BY Cluster ORDER BY iSequence) + fValue) / 2 as fValueAjusted

It takes the previous (based on iSequence) record's fValue, sums with current one, and divides it by 2.

But, instead of using fValue, I must do that using previous record's fValueAjusted.

It means that first record's fValueAjusted will be its own fValue. Second record's fValueAjusted will be based on first record's fValue. And, starting from third record, it's calculation will be based on previous record's fValueAjusted.

I need fValueAjusted to be calculated recursively over the previous record's fValueAjusted. I can't figure out how to do that.

Update 1: This is an example of source data. Real table has hundreds of records and 80 clusters.

CREATE TABLE dbo.example (
    iUnity      int NOT NULL,
    Cluster     char(2) NOT NULL,
    fValue      float NOT NULL
)

15  A1      150
17  A1      170
21  B2      210
23  B2      230
71  C3      710

This is the CTE that calculates the sequence:

WITH cteSequencing AS (
    SELECT
        iUnity,Cluster
        ,fValue as fValueOriginal
        ,row_number() OVER (PARTITION BY Cluster ORDER BY fValueOriginal) as iSequence
    FROM dbo.example
)

If fValueAjusted would be calculated based on fValueOriginal, the query would look like:

SELECT
    iUnity,Cluster,fValueOriginal
    ,(
        lag(fValue,1,fValue) OVER (PARTITION BY Cluster ORDER BY iSequence)
        + fValueOriginal
    ) / 2 as fValueAjusted
FROM cteSequencing

But fValueAjusted of one record must be calculated based on fValueAjusted of previous record. It would be something like:

SELECT
    iUnity,Cluster,fValueOriginal
    ,(
        lag(fValueAjusted,1,fValueOriginal) OVER (PARTITION BY Cluster ORDER BY iSequence)
        + fValueOriginal
    ) / 2 as fValueAjusted
FROM cteSequencing

Of course fValueAjusted isn't available when it executes. LAG() must go recursively, calculating the column for a record then providing this column for next record to use.

回答1:

UPDATE: Original Answer was not correct

Here is the correct one:

The code uses recursive CTEs

CREATE TABLE #example (
    iUnity      int NOT NULL,
    Cluster     char(2) NOT NULL,
    fValue      float NOT NULL
)
INSERT INTO #example
VALUES
( 15,  'A1',      150 ),
( 16,  'A1',      170 ),
( 17,  'A1',      190 ),
( 18,  'A1',      210 ),
( 21,  'B2',      210 ),
( 23,  'B2',      230 ),
( 71,  'C3',      710 )

WITH cteSequencing AS (
    -- Get Values Order
    SELECT iUnity, Cluster, fValue, fValue AS fValueAjusted,
        ROW_NUMBER() OVER (PARTITION BY Cluster ORDER BY fValue) AS iSequence
    FROM #example
),
Recursion AS(
    -- Anchor - the first value in clusters
    SELECT iUnity, Cluster, fValue, fValueAjusted, iSequence
    FROM cteSequencing
    WHERE iSequence = 1
    UNION ALL
    -- Calculate next value based on the previous
    SELECT b.iUnity As iUnity, b.Cluster, b.fValue,
        ( a.fValueAjusted + b.fValue ) / 2 AS fValueAjusted,
        b.iSequence
    FROM Recursion AS a
        INNER JOIN cteSequencing AS b ON a.iSequence + 1 = b.iSequence AND a.Cluster = b.Cluster
)
SELECT * FROM Recursion ORDER BY Cluster, fValue

-- Manually check results
SELECT ( 150 + 170 ) / 2
SELECT ( 190 + 160 ) / 2 
SELECT ( 190 + 170 ) / 2

Output:

iUnity      Cluster fValue                 fValueAjusted          iSequence
----------- ------- ---------------------- ---------------------- --------------------
15          A1      150                    150                    1
16          A1      170                    160                    2
17          A1      190                    175                    3
18          A1      210                    192.5                  4
21          B2      210                    210                    1
23          B2      230                    220                    2
71          C3      710                    710                    1