问题
i have this piece of code:
begin
complete_results = Timeout.timeout(4) do
results = platform.search(artist, album_name)
end
rescue Timeout::Error
puts 'Print me something please'
end
I then launch the method containing this code, and well, here is the beginning of a stack trace:
Exception message : execution expired Exception backtrace : /***/****/.rvm/rubies/ruby-1.8.7-p302/lib/ruby/1.8/timeout.rb:64:i
So i naively thinks that my call timeouted. But 'Print me something please' is never printed and complete_results
wich is suppose to be the timeout status return value (either true or false, as mentionned in the documentation), is definitively not a boolean.
Am I doing something wrong?
回答1:
Your code is correct
require 'timeout'
begin
complete_results = Timeout.timeout(1) do
sleep(2)
end
rescue Timeout::Error
puts 'Print me something please'
end
does print out "print me something please".
Try the basic code as above. If that works, you have an issue in platform.search
.
回答2:
The problem is that platform.search
is catching the exception that Timeout#timeout throws
.
You can get around this by wrapping your inner code in another thread -- YMMV.
begin
complete_results = Timeout.timeout(4) do
Thread.new{ results = platform.search(artist, album_name) }.value
end
rescue Timeout::Error
puts 'Print me something please'
end
回答3:
According to the documentation:
If the block execution terminates before sec seconds has passed, it returns true. If not, it terminates the execution and raises exception (which defaults to Timeout::Error)
This means it only returns true if it's successful, otherwise the variable will not be set (ie it's nil NOT false).
As far as your example goes, it's definitely timing out for me and getting to the rescue part...
来源:https://stackoverflow.com/questions/4637282/ruby-timeouttimeout-doesnt-fire-exception-and-doesnt-return-what-documented