问题
One of the question asked in an interview was,
One table has 100 records. 50 of them are duplicates. Is it possible with a single query to delete the duplicate records from the table as well as select and display the remaining 50 records.
Is this possible in a single SQL query?
Thanks
SNA
回答1:
with SQL Server you would use something like this
DECLARE @Table TABLE (ID INTEGER, PossibleDuplicate INTEGER)
INSERT INTO @Table VALUES (1, 100)
INSERT INTO @Table VALUES (2, 100)
INSERT INTO @Table VALUES (3, 200)
INSERT INTO @Table VALUES (4, 200)
DELETE FROM @Table
OUTPUT Deleted.*
FROM @Table t
INNER JOIN (
SELECT ID = MAX(ID)
FROM @Table
GROUP BY PossibleDuplicate
HAVING COUNT(*) > 1
) d ON d.ID = t.ID
The OUTPUT statement shows the records that get deleted.
Update:
Above query will delete duplicates and give you the rows that are deleted, not the rows that remain. If that is important to you (all in all, the remaining 50 rows should be identical to the 50 deleted rows), you could use SQL Server's 2008 MERGE syntax to achieve this.
回答2:
Lieven's Answer is a good explanation of how to output the deleted rows. I'd like to add two things:
If you want to do something more with the output other than displaying it, you can specify
OUTPUT INTO @Tbl
(where@Tbl
is a table-var you declare before the deleted);Using
MAX
,MIN
, or any of the other aggregates can only handle one duplicate row per group. If it's possible for you to have many duplicates, the following SQL Server 2005+ code will help do that:
;WITH Duplicates AS
(
SELECT
ID,
ROW_NUMBER() OVER (PARTITION BY DupeColumn ORDER BY ID) AS RowNum
)
DELETE FROM MyTable
OUTPUT deleted.*
WHERE ID IN
(
SELECT ID
FROM Duplicates
WHERE RowNum > 1
)
回答3:
Sounds unlikely, at least in ANSI SQL, since a delete only returns the count of the number of deleted rows.
来源:https://stackoverflow.com/questions/2152923/single-query-to-delete-and-display-duplicate-records