问题
I'm trying to write TIFF IFDs, and I'm looking for a simple way to do the following (this code obviously is wrong but it gets the idea across of what I want):
out.writeChar(12) (bytes 0-1)
out.writeChar(259) (bytes 2-3)
out.writeChar(3) (bytes 4-5)
out.writeInt(1) (bytes 6-9)
out.writeInt(1) (bytes 10-13)
Would write:
0c00 0301 0300 0100 0000 0100 0000
I know how to get the writing method to take up the correct number of bytes (writeInt, writeChar, etc) but I don't know how to get it to write in little endian. Anyone know?
回答1:
Maybe you should try something like this:
ByteBuffer buffer = ByteBuffer.allocate(1000);
buffer.order(ByteOrder.LITTLE_ENDIAN);
buffer.putChar((char) 12);
buffer.putChar((char) 259);
buffer.putChar((char) 3);
buffer.putInt(1);
buffer.putInt(1);
byte[] bytes = buffer.array();
回答2:
ByteBuffer is apparently the better choice. You can also write some convenience functions like this,
public static void writeShortLE(DataOutputStream out, short value) {
out.writeByte(value & 0xFF);
out.writeByte((value >> 8) & 0xFF);
}
public static void writeIntLE(DataOutputStream out, int value) {
out.writeByte(value & 0xFF);
out.writeByte((value >> 8) & 0xFF);
out.writeByte((value >> 16) & 0xFF);
out.writeByte((value >> 24) & 0xFF);
}
回答3:
Check out ByteBuffer, specifically the 'order' method. ByteBuffer is a blessing for those of us who need to interface with anything not Java.
来源:https://stackoverflow.com/questions/1394735/java-writing-in-file-little-endian