问题
When this variable becomes a certain amount i want the loop to stop, but i keep getting the error, "Uncaught SyntaxError: Illegal break statement".
function loop() {
if (isPlaying) {
jet1.draw();
drawAllEnemies();
requestAnimFrame(loop);
if (game==1) {
break;
}
}
}
回答1:
break is to break out of a loop like for, while, switch etc which you don't have here, you need to use return
to break the execution flow of the current function and return to the caller.
function loop() {
if (isPlaying) {
jet1.draw();
drawAllEnemies();
requestAnimFrame(loop);
if (game == 1) {
return
}
}
}
Note: This does not cover the logic behind the if condition or when to return from the method, for that we need to have more context regarding the drawAllEnemies
and requestAnimFrame
method as well as how game
value is updated
回答2:
You need to make sure requestAnimFrame stops being called once game == 1. A break statement only exits a traditional loop (e.g. while()
).
function loop() {
if (isPlaying) {
jet1.draw();
drawAllEnemies();
if (game != 1) {
requestAnimFrame(loop);
}
}
}
Or alternatively you could simply skip the second if
condition and change the first condition to if (isPlaying && game !== 1)
. You would have to make a variable called game and give it a value of 0. Add 1 to it every game.
回答3:
I have a function next()
which will maybe inspire you.
function queue(target) {
var array = Array.prototype;
var queueing = [];
target.queue = queue;
target.queued = queued;
return target;
function queued(action) {
return function () {
var self = this;
var args = arguments;
queue(function (next) {
action.apply(self, array.concat.apply(next, args));
});
};
}
function queue(action) {
if (!action) {
return;
}
queueing.push(action);
if (queueing.length === 1) {
next();
}
}
function next() {
queueing[0](function (err) {
if (err) {
throw err;
}
queueing = queueing.slice(1);
if (queueing.length) {
next();
}
});
}
}
来源:https://stackoverflow.com/questions/22549032/illegal-use-of-break-statement-javascript