Forking python, defunct child

问题

I have some troubles with Python child processes so I wrote a very simple script:

import os
import sys
import time

pid = os.fork()
if pid:
    #parent
    time.sleep(30)
else:
    #child
    #os._exit(0)
    sys.exit()

While parent process is sleeping I launch

ps fax | grep py[t]hon

And I read this output

2577 ?        S      0:00 python /home/pi/python/GPIO/GPIODaemon.py restart
2583 ?        Z      0:00  \_ [python] <defunct>

Using sys.exit()oros._exit(0) there is always a Zombie process and I'm unable to understand why.

Working on my more complex code I was thinking that there was some resources that child processes were keeping locked, but on this simplified code child has no file/socket/db connection at all! Why is child process zombiefied?

回答1:

To clear the child process in Unix you need to wait on the child, check one of the os.wait(), os.waitpid(), os.wait3() or os.wait4() at http://docs.python.org/2/library/os.html#os.wait

As to why this is so, this is a design decision of Unix. The child process keeps its return value in its process state, if it was to disappear you'll have no return value. The os.wait() also returns to you the return value and then the child process is released and all associated resources are released.

回答2:

I just had a similar problem: A process started by spawnl, which might end or might need to be terminated at a specific point. My solution to not have all the zombie processes was

def cleanup_subprocesses(self, pid):
  try:
    os.kill(pid, signal.SIGKILL)
  except OSError:
    pass
  os.waitpid(self._pid, 0)

If the process did not end in time, it gets killed, in any case, the waitpid-command is executed.

This does obviously not help, if there is no good point in your program, where you know, that you don’t need the process anymore.

来源：https://stackoverflow.com/questions/18090230/forking-python-defunct-child

标签

python

fork

zombie-process