How can I prevent Hibernate from updating NULL values

半世苍凉 提交于 2019-12-20 09:48:26

问题


Is there a setting in hibernate to ignore null values of properties when saving a hibernate object?

NOTE
In my case I am de-serializing JSON to a Hibernate Pojo via Jackson.

The JSON only contains some of the fields of the Pojo. If I save the Pojo the fields that were not in the JSON are null in the Pojo and hibernate UPDATES them.

I came accross the setting updateable=false, but this isn't a 100% solution. http://docs.jboss.org/hibernate/stable/annotations/reference/en/html_single/#entity-mapping-property

Maybe somebody has another idea...

NOTE 2:

According to the Hibernate Docs the dynamicUpdate annotation does exactly that

dynamicInsert / dynamicUpdate (defaults to false):
specifies that INSERT / UPDATE SQL should be generated at runtime and contain only the columns whose values are not null.

http://docs.jboss.org/hibernate/core/3.6/reference/en-US/html_single/#mapping-declaration-class

Funny enough if you define it in XML via dynamic-update the docu do not mention the hanlding of NULL values.

dynamic-update (optional - defaults to false):
specifies that UPDATE SQL should be > generated at runtime and can contain only those columns whose values have changed.

Due to the fact that I'm using both annotations AND xml configuration, hibernate seems to ignores my dynamicUpdate=true annotation.


回答1:


You should first load the object using the primary key from DB and then copy or deserialize the JSON on top of it.

There is no way for hibernate to figure out whether a property with value null has been explicitly set to that value or it was excluded.

If it is an insert then dynamic-insert=true should work.




回答2:


I have googled a lot about this,but there is no the very solution for me.So,I used a not graceful solution to cover it.

  public void setAccount(Account a) throws HibernateException {
    try {
        Account tmp = (Account) session.
                get(Account.class, a.getAccountId());
        tmp.setEmail(getNotNull(a.getEmail(), tmp.getEmail()));            
        ...
        tmp.setVersion(getNotNull(a.getVersion(), tmp.getVersion()));
        session.beginTransaction();
        session.update(tmp);
        session.getTransaction().commit();
    } catch (HibernateException e) {
        logger.error(e.toString());
        throw e;
    }
}

public static <T> T getNotNull(T a, T b) {
    return b != null && a != null && !a.equals(b) ? a : b;
}

I receive an Object a which contains a lot of fields.Those field maybe null,but I don't want to update them into mysql. I get an tmp Obejct from db, and change the field by method getNotNull,then update the Object.

a Chinese description edition




回答3:


I bumped into this problem and I did a work-around to help myself through this. May be a little ugly but may work just fine for you too. Kindly if someone feels there's an adjustment that's good to have feel free to add. Note that the work-around is meant for valid entity classes and whose some fields include nullable attributes. Advantage with this one is it reduces the number of queries.

public String getUpdateJPQL(Object obj, String column, Object value) throws JsonProcessingException, IOException {

//obj -> your entity class object
//column -> field name in the query clause
//value -> value of the field in the query clause

    ObjectMapper mapper = new ObjectMapper();
    String json = mapper.writeValueAsString(obj);
    Map<String, Object> map = mapper.readValue(json, Map.class);
    Map format = new HashMap();
    if (value instanceof String) {
        value = "'" + value + "'";
    }

    map.keySet()
            .forEach((str) -> {
                Object val = map.get(str);
                if (val != null) {
                    format.put("t.".concat(str), "'" + val + "'");
                }
            });
    String formatStr = format.toString();
    formatStr = formatStr.substring(1, formatStr.length() - 1);

    return "update " + obj.getClass()
            .getSimpleName() + " t set " + formatStr + " where " + column + " = " + value + "";

}

Example: For entity type User with fields: userId, userName & userAge; the result query of getUpdateJPQL(user, userId, 2) should be update User t set t.userName = 'value1', t.userAge = 'value2' where t.userId = 2 Note that you can use json annotations like @JsonIgnore on userId field to exclude it in deserialization i.e. in the generated query. You can then run your query using entityManager or hibernate sessions.



来源:https://stackoverflow.com/questions/7517546/how-can-i-prevent-hibernate-from-updating-null-values

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!