问题
following Convert decimal to hexadecimal in UNIX shell script
I am trying to print only the hex values from hexdump, i.e. don't print the lines numbers and the ASCII table.
But the following command line doesn't print anything:
hexdump -n 50 -Cs 10 file.bin | awk '{for(i=NF-17; i>2; --i) print $i}'
回答1:
You can specify the exact format that you want hexdump to use for output, but it's a bit tricky. Here's the default output, minus the file offsets:
hexdump -e '16/1 "%02x " "\n"' file.bin
(To me, it looks like this would produce an extra trailing space at the end of each line, but for some reason it doesn't.)
回答2:
Using xxd is better for this job:
xxd -p -l 50 -seek 10 file.bin
From man xxd:
xxd - make a hexdump or do the reverse.
-p | -ps | -postscript | -plain
output in postscript continuous hexdump style. Also known as plain hexdump style.
-l len | -len len
stop after writing <len> octets.
-seek offset
When used after -r: revert with <offset> added to file positions found in hexdump.
回答3:
As an alternative, consider using xxd -p file.bin.
回答4:
First of all, remove -C which is emitting the ascii information.
Then you could drop the offset with
hexdump -n 50 -s 10 file.bin | cut -c 9-
来源：https://stackoverflow.com/questions/15553493/how-to-print-only-the-hex-values-from-hexdump-without-line-numbers-or-ascii-tabl