Gulp.js event stream merge order

问题

I am trying to merge css and scss files into a main.css file that goes in my build directory. Its working, but not in the right order. The style attributes from the scss files need to be in the bottom of the main.css file so they overrule the rest.

my Gulp task looks like this:

    //CSS
gulp.task('css', function () {
    var cssTomincss = gulp.src(['dev/css/reset.css', 'dev/css/style.css','dev/css/typography.css',    'dev/css/sizes.css']);

    var cssFromscss = gulp.src(['dev/css/*.scss'])
        .pipe(sass());

    return es.merge(cssTomincss, cssFromscss)
        .pipe(concat('main.css'))
        .pipe(minifyCSS())
        .pipe(gulp.dest('build/css'))
});

I am defining the sources first with variables. I am using the gulp-sass plugin to convert the scss file into normal css (.pipe(sass)) and later merging the two with the es.merge function and concatenating them into main.css.

The problem is that the style attributes van the .scss files end up somewhere in the top end of the main.css file. I need them to be at the bottom. So they need to be concatenated at the bottom.

Any clue on how to do this?

回答1:

Try streamqueue.

var streamqueue = require('streamqueue');

gulp.task('css', function () {
    return streamqueue({ objectMode: true },
            gulp.src(['dev/css/reset.css', 'dev/css/style.css', 'dev/css/typography.css', 'dev/css/sizes.css']),
            gulp.src(['dev/css/*.scss']).pipe(sass())
        )
        .pipe(concat('main.css'))
        .pipe(minifyCSS())
        .pipe(gulp.dest('build/css'))
});

This cheatsheet will help you. PDF is here.

回答2:

It seems that the plugin gulp-order fits perfectly well in your case.

It allows you to re-order the passed stream with your own glob pattern, for example based on your code :

return es.merge(cssTomincss, cssFromscss)
    .pipe(order([
      'dev/css/reset.css',
      'dev/css/style.css',
      'dev/css/typography.css',
      'dev/css/sizes.css',
      'dev/css/*.css',
    ]))
    .pipe(concat('main.css'))
    .pipe(minifyCSS())
    .pipe(gulp.dest('build/css'))

One drawback of this is that you have to re-declare your globs, but you can get around by assign your globs to a value and then concat them in you order pipe, much cleaner.

You may have to set the base option to . of gulp-order as stated in their Readme if the files were not ordered correctly.

One another way would be to use stream-series, basically the same as event-stream, but the order of your stream is preserved, and you don't have to rewrite your globs.

回答3:

I tried gulp-order without success: the order somehow wasn't taken into account.

The solution which worked for me was using stream-series, mentioned by Aperçu.

return streamSeries(
    cssTomincss,
    cssFromscss)
    .pipe(concat('main.css'))
    .pipe(minifyCSS())
    .pipe(gulp.dest('build/css'));

回答4:

I failed with all provided answers, they produced some silent errors. Finally merge2 worked for me (seems like there was gulp-merge and later the project was renamed into merge2). I'm not sure why there is a need in streamify plugin, e.g. streams created with Rollup may produce "stream-not-supported-errors" with gulp-concat, gulp-uglify or gulp-insert.

const mergeStreams = require('merge2');
const streamify = require('streamify');
...
gulp.task('build', () => {
    const streams = sources.map(createJSFile);
    return mergeStreams(...streams)
        .pipe(streamify(concat('bundle.js')))
        .pipe(streamify(uglify()))
        .pipe(gulp.dest('./dist'));
});

来源：https://stackoverflow.com/questions/26088718/gulp-js-event-stream-merge-order