问题
In Windows for ASP, you can get it perfmon, but...
How to get "requests per second" for Apache in Linux?
回答1:
In realtime, or can you use mod_status?
And apparently, there is a version of top for apache...
回答2:
Here is a short bash script I made up to sample the request rate (based on dicroce's suggestion of using wc -l on the log file).
#!/bin/sh
##############################################################################
# This script will monitor the number of lines in a log file to determine the
# number of requests per second.
#
# Example usage:
# reqs-per-sec -f 15 -i /var/www/http/access.log
#
# Author: Adam Franco
# Date: 2009-12-11
# License: http://www.gnu.org/copyleft/gpl.html GNU General Public License (GPL)
##############################################################################
usage="Usage: `basename $0` -f <frequency in seconds, min 1, default 60> -l <log file>"
# Set up options
while getopts ":l:f:" options; do
case $options in
l ) logFile=$OPTARG;;
f ) frequency=$OPTARG;;
\? ) echo -e $usage
exit 1;;
* ) echo -e $usage
exit 1;;
esac
done
# Test for logFile
if [ ! -n "$logFile" ]
then
echo -e $usage
exit 1
fi
# Test for frequency
if [ ! -n "$frequency" ]
then
frequency=60
fi
# Test that frequency is an integer
if [ $frequency -eq $frequency 2> /dev/null ]
then
:
else
echo -e $usage
exit 3
fi
# Test that frequency is an integer
if [ $frequency -lt 1 ]
then
echo -e $usage
exit 3
fi
if [ ! -e "$logFile" ]
then
echo "$logFile does not exist."
echo
echo -e $usage
exit 2
fi
lastCount=`wc -l $logFile | sed 's/\([0-9]*\).*/\1/'`
while true
do
newCount=`wc -l $logFile | sed 's/\([0-9]*\).*/\1/'`
diff=$(( newCount - lastCount ))
rate=$(echo "$diff / $frequency" |bc -l)
echo $rate
lastCount=$newCount
sleep $frequency
done
回答3:
To sum up, you can use mod_status and apachetop.
Alternatively, you can use Adam Franco's and Jon Daniel's nice scripts to have a live look.
If you would like to have a look at a partiular date and hour, you can issue this little command:
grep "29/Oct/2014:12" /var/log/apache2/example.com.log | cut -d[ -f2 | cut -d] -f1 | awk -F: '{print $2":"$3}' | sort -nk1 -nk2 | uniq -c | awk '{ if ($1 > 10) print $0}'
Replace with the date and hour you are interested and also with the proper pathfilename of the log file.
It will print out something like:
1913 12:47
226 12:48
554 12:49
918 12:50
There is a nice article here with more options on using a combination of awk, cut and uniq commands to get quick stats of the kind.
回答4:
You can use 'wc -l' on the access log to get the number of lines (which roughly corresponds to the number of requests...) Do that every minute and subtract the last value to get the delta...
回答5:
I think mod_status can do it ...
http://httpd.apache.org/docs/2.0/mod/mod_status.html
You can also use zenoss to collect data from mod_status using the community apache plugin.
http://www.zenoss.com/
回答6:
Script shows inconsistent numbers. -f parameter affects output a lot! and first reading is not accurate either.
I ended up using:
while true; do tail -n0 -f access.log>/tmp/tmp.log & sleep 2; kill $! ; wc -l /tmp/tmp.log | cut -c-2; done 2>/dev/null
Found here.
回答7:
I didn't like any of the solutions I found, so I wrote my own.
- mod_status isn't really accurate enough. It's based on how long the server is up, which in our case is normally months. What I'm looking for is traffic spikes.
- the shell script above uses a sleep() statement which isn't ideal as it takes x seconds to actually retrieve the data.
So this solution takes a particular line in the access_log 15000 requests ago, and uses the time recorded to compare with the current time.
# This check is needed because if the logs have just rolled over, then we need a minimum
# amount of data to report on.
# You will probably need to adjust the 3500000 - this is roughly the file size when the
# log file hits 15000 requests.
FILESIZE=`ls -l /var/log/httpd/access_log | awk '{print $5}' `
if [ $FILESIZE -le 3500000 ]
then
# not enough data - log file has rolled over
echo "APACHE_RPS|0"
else
# Based on 15000 requests. Depending on the location of the date field in
# your apache log file you may need to adjust the ...substr($5... bit
LASTTIME=`tail -15000 /var/log/httpd/access_log | head -1 | awk '{printf("%s\n",substr($5,2,20));}' `
APACHE_RPS=`echo $LASTTIME | gawk -vREQUESTS=15000 ' {
# convert apache datestring into time format accepted by mktime();
monthstr = substr($0,4,3);
if(monthstr == "Jan"){ monthint = "01"; }
if(monthstr == "Feb"){ monthint = "02"; }
if(monthstr == "Mar"){ monthint = "03"; }
if(monthstr == "Apr"){ monthint = "04"; }
if(monthstr == "May"){ monthint = "05"; }
if(monthstr == "Jun"){ monthint = "06"; }
if(monthstr == "Jul"){ monthint = "07"; }
if(monthstr == "Aug"){ monthint = "08"; }
if(monthstr == "Sep"){ monthint = "09"; }
if(monthstr == "Oct"){ monthint = "10"; }
if(monthstr == "Nov"){ monthint = "11"; }
if(monthstr == "Dec"){ monthint = "12"; }
mktimeformat=sprintf("%s %s %s %s %s %s [DST]\n", substr($0,8,4), monthint, substr($0,1,2), substr($0, 13,2), substr($0, 16,2), substr($0, 19,2) );
# calculate difference
difference = systime() - mktime(mktimeformat);
# printf("%s - %s = %s\n",systime(), mktime(mktimeformat), difference);
printf("%s\n",REQUESTS/difference);
} ' `
echo "APACHE_RPS|${APACHE_RPS}"
fi
回答8:
I wrote a set of Perl scripts that show the average requests-per-second for the past 1, 5 and 15 minutes (like top). It's at https://gist.github.com/1040144 .
回答9:
mod_status is the one! if you call it with:
http://{ip}/server-status?refresh=1&auto-refresh=true
Then it auto refreshes every 2 seconds so you can see a constant realtime view :-)
来源：https://stackoverflow.com/questions/345546/how-to-get-requests-per-second-for-apache-in-linux