问题
OVERVIEW: I have a form that includes 5 file upload fields. A php script processes the data and sends out 2 emails (one to the admin and a confirmation receipt to the user) AND appends the data to a .csv file on the server.
QUESTION: How do I get the URL of the uploaded files in to a variable that I can use to populate the email and .csv file.
Everything is working great except I need a link to each of the the uploaded files included in the emails and in the .csv file. I cannot seem to figure that part out after a couple days of trying.
SIMPLIFIED HTML FORM:
<HTML><head><title>MultiFile Upload and Send Email</title></head><body>
<form method='post' action='php/multiUploadTestProcess.php' multipart='' enctype='multipart/form-data'>
<label for ='exhName'>Exhibitor Name:</label>
<input type='text' name='exhName' multiple class='form-control'><br><br>
Select File 1: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
Select File 2: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
Select File 3: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
Select File 4: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
Select File 5: <input type='file' name='img[]' multiple class='form-control' size='10'><br><br>
<input type='submit' value='upload'>
</form>
THE PHP: NOTE: I've removed all the validation/sanitizing, removed .csv appending, and the second email submission. I'm assuming once we can get the links in to one email the rest will be pretty much the same.
<?php
$exhName = $_POST['exhName'];
$exhNameNoSpace = str_replace(" ","-", $exhName);
$img = $_FILES['img'];
$to = 'DESTINATION-EMAIL@DOMAIN.com';
$subject = 'New File Uploads';
$email = 'ReplyYToEMAIL@DOMAIN.com';
if(!empty($img))
{
/* reArrayFiles changes the array pattern for PHP's $_FILES (see function at end) */
$img_desc = reArrayFiles($img);
print_r($img_desc);
/* RENAME EACH FILE to current date, exhibitor name w/o spaces, and random integer string (ensuring no file overwrites). Then MOVE FILE to uploads */
foreach($img_desc as $val)
{
$newname = date('m-d-Y',time()).'-'.$exhNameNoSpace.'-'.mt_rand().'.jpg';
move_uploaded_file($val['tmp_name'],'../uploads/'.$newname);
/* THIS FOLLOWING LINE WAS MY ATTEMPT AT GETTING A LINK TO EACH UPLOADED FILE BUT IS NOT WORKING. AND THE VARIABLE $newname HERE IS ADDING A NEW RANDOM INT TO THE FILENAME - NOT THE ONE THE FILE WAS SAVED WITH. */
$filePath = '**Full Path To Directory**'.$newname;
}
/* SEND EMAIL TO ADMIN */
$emailText = "=============================================\nYou have a new Market Place Application\n".
"Here are the details:\n=============================================\n\n Exhibitor Name: $exhName \n\n Upload File 1: $filePath \n\n Upload File 2: $filePath \n\n ###";
// All the neccessary headers for the email.
$headers = array('Content-Type: text/plain; charset="UTF-8";',
'From: ' . $email,
'Reply-To: ' . $email,
'Return-Path: ' . $email,
);
$emailText = wordwrap($emailText, 70);
// Send email
mail($to, $subject, $emailText, implode("\n", $headers));
/* END SEND EMAIL TO ADMIN */
}
function reArrayFiles($file)
{
$file_ary = array();
$file_count = count($file['name']);
$file_key = array_keys($file);
for($i=0;$i<$file_count;$i++)
{
foreach($file_key as $val)
{
$file_ary[$i][$val] = $file[$val][$i];
}
}
return $file_ary;
}
?>
Help is greatly appreciated!
回答1:
If you want to attach the file to your emails, you may need the fullpath on the server rather than external URL. Have a look at realpath PHP function and try to wrap the path you saved the file into this function call, so making it something like:
$newname = date('m-d-Y',time()).'-'.$exhNameNoSpace.'-'.mt_rand().'.jpg'; move_uploaded_file($val['tmp_name'],'../uploads/'.$newname); /* THIS FOLLOWING LINE WAS MY ATTEMPT AT GETTING A LINK TO EACH UPLOADED FILE BUT IS NOT WORKING. AND THE VARIABLE $newname HERE IS ADDING A NEW RANDOM INT TO THE FILENAME - NOT THE ONE THE FILE WAS SAVED WITH. */ $filePath = realpath('../uploads/'.$newname);
after this $filepath should contain the full path to the uploaded file on the server.
- If you wish to add a link with an external URL into your mails, you really need the full URL, but it depends on the domain name and the location of uploads folder relatively to the root (/) of your domain. It should be something like http://example.com/uploads/11-16-2018-name-6534.jpg and you can figure it out by testing the access to the generated filenames via your browser, assuming your uploads folder is accessible through the webserver. Once you figure out the URL you may either save the domain and path into your config file or you may check if
$_SERVER['SERVER_NAME']contains the domain name and append it with the path then.
In order to use the URLs in the email text you need to modify your code like:
$emailText = "=============================================\nYou have a new Market Place Application\nHere are the details:\n=============================================\n\n Exhibitor Name: $exhName \n\n ";
$i = 1;
foreach($img_desc as $val)
{
$newname = date('m-d-Y',time()).'-'.$exhNameNoSpace.'-'.mt_rand().'.jpg';
move_uploaded_file($val['tmp_name'],'../uploads/'.$newname);
/* THIS FOLLOWING LINE WAS MY ATTEMPT AT GETTING A LINK TO EACH UPLOADED FILE BUT IS NOT WORKING. AND THE VARIABLE $newname HERE IS ADDING A NEW RANDOM INT TO THE FILENAME - NOT THE ONE THE FILE WAS SAVED WITH. */
$filePath = '**Full Path To Directory**'.$newname;
$emailText .= "Upload File " . $i . ": " . $filePath . "\n\n";
$i++;
}
// All the neccessary headers for the email.
$headers = array('Content-Type: text/plain; charset="UTF-8";',
'From: ' . $email,
'Reply-To: ' . $email,
'Return-Path: ' . $email,
);
$emailText = wordwrap($emailText, 70);
// Send email
mail($to, $subject, $emailText, implode("\n", $headers));
来源：https://stackoverflow.com/questions/53344213/how-can-i-get-the-url-of-each-uploaded-file-and-send-through-email