问题
I have a matrix that holds 1:s or 0:s, creating binary numbers. Its width is n. For n = 2 and n = 3 it would look like:
00 000
01 001
10 010
11 011
100
101
110
111
and so on. Right now I'm using the following code to produce this.
int row = (int) Math.pow(2, n);
int col = n;
int[][] matrix = new int[row][col];
for (int r = 0; r < row; r++) {
String binaryNumber = String.format("%" + n + "s", Integer.toBinaryString(r)).replace(' ', '0');
for (int c = col - 1; c >= 0; c--) {
matrix[r][c] = Integer.parseInt("" + binaryNumber.charAt(0));
binaryNumber = binaryNumber.substring(1);
}
}
Now I need help with creating the same thing but gray-coded. Is there a convenient way to do this in java? Also, if there is a smarter way to do what I'm doing above I'd love to learn.
I don't really have a clue where to start since I'm used to having toBinaryString()
helping me. EDIT: The gray-code will look like this:
00 000
01 001
11 011
10 010
110
111
101
100
回答1:
You can get gray code by simply changing
Integer.toBinaryString(r)
into
Integer.toBinaryString((r >> 1) ^ r)
.
Have a try:)
回答2:
This should do it:
public class GrayCodeMatrix {
public static void main(String[] args) {
// set length (< Integer.SIZE)
final int grayCodeLength = 4;
// generate matrix
final int grayCodeCount = 1 << grayCodeLength; // = 2 ^ grayCodeLength
int grayCodeMatrix[][] = new int[grayCodeCount][grayCodeLength];
for (int i = 0; i < grayCodeCount; i++) {
int grayCode = (i >> 1) ^ i;
for (int j = grayCodeLength-1; j >= 0; j--) {
// extract bit
final int grayCodeBitMask = 1 << j;
grayCodeMatrix[i][j] = (grayCode & grayCodeBitMask) >> j;
}
}
// view result
for (int y = 0; y < grayCodeMatrix.length; y++) {
for (int x = 0; x < grayCodeMatrix[0].length; x++) {
System.out.print(grayCodeMatrix[y][x]);
}
System.out.print("\n");
}
}
}
EDIT: WORKS ONLY FOR grayCodeLength < Integer.SIZE
来源:https://stackoverflow.com/questions/17652524/fill-matrix-with-binary-numbers-regular-and-gray-coded