问题
It's the exercise of "Programming language pragmatics, Michael Scott" .
Q. return a list containing all elements of a given list that satisfy a given predicate. For example, (filter (lambda (x) (< x 5) '(3 9 5 8 2 4 7)) should return (3 2 4).
I think that question require function which satisfy every predicate not only above. But I don't have any idea to implement such function. Please help.
回答1:
The filter procedure already exists in most Scheme implementations, it behaves as expected:
(filter (lambda (x) (< x 5)) '(3 9 5 8 2 4 7))
=> '(3 2 4)
Now, if the question is how to implement it, it's rather simple - I'll give you some hints so you can write it by yourself. The trick here is noticing that the procedure is receiving another procedure as parameter, a predicate in the sense that it'll return #t
or #f
when applied to each of the elements in the input list. Those that evaluate to #t
are kept in the output list, those that evaluate to #f
are discarded. Here's the skeleton of the solution, fill-in the blanks:
(define (filter pred? lst)
(cond (<???> ; if the list is empty
<???>) ; return the empty list
(<???> ; apply pred? on the first element, if it's #t
(cons <???> ; then cons the first element
(filter pred? <???>))) ; and advance recursion
(else (filter pred? <???>)))) ; else just advance recursion
来源:https://stackoverflow.com/questions/15869018/scheme-i-have-no-idea-to-implement-given-function