问题
The question is as simple as the title says,But here is one logic. Here is my code
CREATE TABLE `inf_brand_images` (
`id` bigint(99) NOT NULL AUTO_INCREMENT,
`brand` varchar(255) NOT NULL,
`thumb` text NOT NULL,
`is_active` int(2) NOT NULL DEFAULT '1',
`cmp_brand` varchar(1024) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=6458 DEFAULT CHARSET=latin1
Here is data in this table
ID | brand | thumb |is_active| cmp_brand
1 | NIKE | a.png | 1 |
2 | DUNHILL| b.png | 1 |
3 | NIKE | c.png | 1 | 123_NIKE
4 | NIKE | d.png | 1 | 789_NIKE
cmp_brand is prefixed with some their ids like 123_ and 789_ in my case. Now if i search for NIKE, so I have two parameters,one is NIKE and other is id_NIKE.where id may be 123 or 456 or any other.So for NIKE search i have two parameters,one is brand=NIKE and other is cmp_brand =123_NIKE (i cancatenate id with brand name automatically)
What i want is
IF cmp_brand is '' then compare with brand ELSE compare brand AND cmp_brand.
Here is what i tried,both not working
SELECT thumb
FROM inf_brand_images
where is_active=1 AND
CASE WHEN cmp_brand = '' THEN brand='NIKE'
ELSE cmp_brand='123_NIKE' END
SELECT thumb
FROM inf_brand_images
where is_active=1 AND
((cmp_brand = '' AND brand='NIKE') OR (cmp_brand='123_NIKE'))
回答1:
You are on the right track with your second attempt, using logical AND/OR
groupings instead of a CASE
, but if you want to prefer the row matching cmp_brand
over rows with an empty cmp_brand
and expect only one result back, structure your ORDER BY
to sort the non-empty cmp_brand
first, and limit the overall result to 1.
SELECT thumb
FROM inf_brand_images
WHERE
is_active=1 AND
((cmp_brand = '' AND brand='NIKE') OR (cmp_brand='123_NIKE'))
/* non-empty cmp_brand will sort first */
ORDER BY cmp_brand <> '' DESC
/* and the end result is limited only to the first sorted row
which will be the cmp_brand if matched, or the brand otherwise */
LIMIT 1
http://sqlfiddle.com/#!2/d176b/2
This works because the expression cmp_brand <> ''
evaluates to the boolean true/false
, which MySQL interprets as 1/0
. A descending sort on those values forces the non-empty ones to sort fist (1 before 0).
Update after comments:
Since you do have the possibility of more than one row returned, you cannot rely on the ORDER BY
. Instead, you can perform a LEFT JOIN
against the same table. On one side, match cmp_brand = ''
and on the other side match cmp_brand = '123_NIKE'
. Importantly, return the thumb
column from both sides of the join.
Wrap that in a subquery in the FROM
clause, then at the top level you can use a SELECT CASE
to prefer the cmp_brand
if nonempty.
SELECT DISTINCT
CASE WHEN cbcb IS NOT NULL THEN cbthumb ELSE bthumb END AS thumb
FROM (
/* Return thumbs from both sides of the join */
SELECT
b.thumb AS bthumb,
b.cmp_brand AS bcb,
cb.thumb AS cbthumb,
cb.cmp_brand AS cbcb
FROM
inf_brand_images b
/* join the table against itself with the matching cmp_brand in the join condition */
LEFT JOIN inf_brand_images cb
ON b.brand = cb.brand
AND cb.cmp_brand = '123_NIKE'
WHERE
/* The WHERE clause looks for empty cmp_brand on the left side of the join */
b.brand = 'NIKE' AND b.cmp_brand = ''
) thumbs
- Here is an example where 123_NIKE matches: http://sqlfiddle.com/#!2/dfe228/31
- And an example where 124_NIKE does not match: http://sqlfiddle.com/#!2/dfe228/32
来源:https://stackoverflow.com/questions/22226766/case-in-where-clause-in-mysql