select elements using display:block

问题

This is the html content from which I want to select all elements inside report having display block using jQuery $("#report:visible") does not work for me.

<div id="report">
        <div id="p1" style="display: block;">
            <input id="pname1"  type="checkbox" name="report1">
            <input id="pname2"  type="checkbox" name="report2">
        </div>
        <div id="p2"  style="display: none;">
            <input id="pname1"  type="checkbox" name="report1">
            <input id="pname2"  type="checkbox" name="report2">
        </div>
        <div id="p3"  style="display: none;">
            <input id="pname1"  type="checkbox" name="report1">
            <input id="pname2"  type="checkbox" name="report2">
        </div>
            <div id="p4"  style="display: block;">
            <input id="pname3"  type="checkbox" name="report1">
            <input id="pname4"  type="checkbox" name="report2">
        </div>
</div>

回答1:

Maybe you can use this piece of jQuery :

$("#report div:visible").each(function() { 
    console.log($(this).attr('id')); 
});

Or this one :) ?

$("#report div:visible");

回答2:

$("#report > :visible")

This will select the direct children of #report that are visible. Without the space you're selecting #report itself if it's visible. (Without the > it'd target also the inputs.)

回答3:

You could use:

$("[style='display: block;']");

but I wouldn't, I'd add a class as well to hook onto.

回答4:

You cannot directly select elements in CSS using a property value itself. You can however select by class. The best solution would be to use a class to assign display: block (such as a visible class) and then to select based on its presence or lack thereof.

The other way to do this is to select using the entire value of the style element. But the problem with this is that if you add other inline styles that selector will no longer work. You could then get into regex parsing the style attribute but in my opinion applying a visible or hidden class is far easier and will perform significantly better.

Note that another advantage of using the visible or hidden class is that you can turn it on and off with JavaScript very easily:

document.getElementById("id").classList.toggle("hidden");

回答5:

This may help you with several selectors CSS Selectors.

As for your requirement, You can use this to select all div with display:block under the #report.

$('#report div[style*=display:block]')

回答6:

Why not just

$('#report div:visible');

if markup stays like that it will work. If not just add a class to the report entries like 'entry' then do

$('#report .entry:visible');

回答7:

This should work:

$("#report *").filter(function(){
    $(this).css("display") === "block";
});

The * selects all elements within the #report. You're then filtering them to those with CSS property set to block.

回答8:

Use :visible in place of [style*="display:block"] as it will work in all browsers including IE. [style*="display:block"] will not work in IE.

来源：https://stackoverflow.com/questions/14398444/select-elements-using-displayblock

标签

jquery

jquery-selectors