pandas convert from datetime to integer timestamp

為{幸葍}努か 提交于 2019-12-19 19:44:12

问题


Considering a pandas dataframe in python having a column named time of type integer, I can convert it to a datetime format with the following instruction.

df['time'] = pandas.to_datetime(df['time'], unit='s')

so now the column has entries like: 2019-01-15 13:25:43.

What is the command to revert the string to an integer timestamp value (representing the number of seconds elapsed from 1970-01-01 00:00:00)?

I checked pandas.Timestamp but could not find a conversion utility and I was not able to use pandas.to_timedelta for this.

Is there any utility for this conversion?


回答1:


You can typecast to int using astype(int) and divide it by 10**9 to get the number of seconds to the unix epoch start.

import pandas as pd
df = pd.DataFrame({'time': [pd.to_datetime('2019-01-15 13:25:43')]})
df_unix_sec = pd.to_datetime(df['time']).astype(int)/ 10**9
print(df_unix_sec)



回答2:


Use .dt.total_seconds() on a timedelta64:

import pandas as pd
df = pd.DataFrame({'time': [pd.to_datetime('2019-01-15 13:25:43')]})

# pd.to_timedelta(df.time).dt.total_seconds() # Is deprecated
(df.time - pd.to_datetime('1970-01-01')).dt.total_seconds()

Output

0    1.547559e+09
Name: time, dtype: float64



回答3:


The easiest way is to use .value

pd.to_datetime('1970-01-01').value


来源:https://stackoverflow.com/questions/54312802/pandas-convert-from-datetime-to-integer-timestamp

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