问题
I am using Following Code to start setting I want to launch the setting activity which is started by android ins
PackageList allowedAppsPackageName=CallHelper.Ds.getPackageList();
PackageManager manager = CallDetectService.packageManager;
Intent mainIntent = new Intent(Intent.ACTION_MAIN, null);
mainIntent.addCategory(Intent.CATEGORY_LAUNCHER);
final List<ResolveInfo> apps = manager.queryIntentActivities(mainIntent, 0);
Collections.sort(apps, new ResolveInfo.DisplayNameComparator(manager));
final int count = apps.size();
ResolveInfo info=new ResolveInfo();;
GridViewAppList.clear();
for (int i = 0; i < count; i++)
{
info= apps.get(i);
if(info.activityInfo.applicationInfo.packageName.contains("setting"))
break;
}
ApplicationInfo application = new ApplicationInfo();
application.title = info.loadLabel(manager);
application.setActivity(new ComponentName(
packageName,
info.activityInfo.name),
Intent.FLAG_ACTIVITY_NEW_TASK
| Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
application.icon = info.activityInfo.loadIcon(manager);
application.packagename=packageName;
Log.i("PKG", application.packagename+" "+packageName+" "+info.activityInfo.name);
GridViewAppList.add(application);
回答1:
You can use this snippet to open Settings
Activity :
Intent intent=new Intent();
intent.setComponent(new ComponentName("com.android.settings", "com.android.settings.Settings"));
startActivity(intent);
If you do not know what Activity you have to open,you can find it's name and it's package name as I mentioned here.
回答2:
There are many action constants in the Settings class that can be used to create an intent that will start an activity for the provided sub-Setting or simply launch the Settings app depending on the action.
For example:
intent = new Intent(Settings.ACTION_SETTINGS); // ACTION_SETTINGS will start the Settings app
intent = new Intent(Settings.ACTION_WIFI_SETTINGS); // ACTION_WIFI_SETTINGS will show the WiFi settings
来源:https://stackoverflow.com/questions/18160918/start-activity-android-with-class-name