How to parse an ISO8601 date [duplicate]

问题

This question already has answers here:

How to parse a date string into an NSDate object in iOS? (7 answers)

Closed 6 years ago.

I got string of date regarding this format:

2011-12-29T09:09:06-0500

How can I convert this into a date object?

回答1:

Try this solution

NSString *dateString = @"2011-12-29T09:09:06-0500";
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ssZ"];

NSDate *dateFromString = [dateFormatter dateFromString:dateString];    
[dateFormatter release];
NSLog(@" dateFromString %@",dateFromString);

回答2:

NSString *date = [[NSDate date] description];

[NSDateFormatter setDefaultFormatterBehavior:NSDateFormatterBehavior10_4];
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'"];

NSDate *dateFromString = [[NSDate alloc] init];
dateFromString = [dateFormatter dateFromString:<NSString containing date>];

来源：https://stackoverflow.com/questions/8676672/how-to-parse-an-iso8601-date