问题
I'm trying to convert a HEX number into a short (2 Bytes) using C++ everything is OK except for one thing... signed conversion from short to Byte (last test)
i found this question and couldn't really benefit from it: portable signed/unsigned byte cast,C++
here are my tests:
// test 1 - positive B2Short (success)
byte *b = new byte[2];
b[0] = 0x10; //low byte
b[1] = 0x00; //heigh byte
signed short test = 0;
test = ByteToShort(b);
cout << test << endl;
// test 2 - negative B2Short (success)
b[0] = 0xF0; //low byte
b[1] = 0xFF; //heigh byte
test = 0;
test = ByteToShort(b);
cout << test << endl;
// test 3 - positive Short2B (success)
signed short n = 11;
ShortToByte(n, b);
test = ByteToShort(b); // for display to see if it worked
cout << test << endl;
// test 4 - negative Short2B (FAIL!)
n = -11;
ShortToByte(n, b);
test = ByteToShort(b); // for display to see if it worked
cout << test << endl;
functions used:
signed short ByteToShort(byte* bytes){
signed short result = 0;
result = (result<<8) + bytes[1]; // heigh byte
result = (result<<8) + bytes[0]; // low byte
return result;
}
void ShortToByte(signed short num, byte* bytes){
bytes[1] = num & 0xFF00; // heigh byte
bytes[0] = num & 0x00FF; // low byte
}
outputs:
16
-16
11
245
回答1:
From ShortToByte
:
bytes[1] = num & 0xFF00; // high byte
You have to shift this to the right 8 bits for the result to fit in a byte. Otherwise you will just get the zeros from the low part.
回答2:
I'd say this would be much easier using a union:
union ShortByteUnion {
signed short asShort;
unsigned char asBytes[2];
};
It takes care of the conversion for you.
回答3:
Just cast the short to byte array.
signed short test = 1234;
byte* b;
b = (byte*) &test;
b[0];//one byte
b[1];//another byte
It's dangerous thing to do this on more than one types of machine, because endianess may vary.
I don't like one-liners, but here they go:
((byte*)&test)[0];
((byte*)&test)[1];
来源:https://stackoverflow.com/questions/10288109/signed-short-to-byte-in-c