问题
I have a question for you!
Normally, if you call a callback function within an OOP context you have to use array(&$this, 'callback_function')
That's what I figured out.
But now I want to call a callback in an external class, due to having to much callback_functions. I want to give them an own class for structure reasons.
I thought: "Ok, make an instance of this class and pass it instead of $this."
So I tried it with array($cb, 'callback_function')
and array($this->cb, 'callback_function')
but it won't work.
What am I doing wrong?
Thanks for your help!
Edit:
In my basic class I have:
function __construct()
{
// some other vars here
$this->cb = new Callback();
}
And calling it with:
$newline = preg_replace_callback("/(^#+) (.*)/", array(&$this->cb, 'callback_heading'), $newline);
And in my callback class I have:
class Callback
{
function __construct()
{
$this->list = array("num" => 0, "dot" => 0, "normal" => 0);
$this->td = array("strike" => false, "bold" => false, "italic" => false, "underline" => false, "code" => false);
}
public function callback_heading($parameter)
{
$hashs = strlen($parameter[1]);
$hashs++;
if($hashs > 6)
$hashs = 6;
return "<h".$hashs."><span class=\'indented\'>".$parameter[1]."</span><strong>".$parameter[2]."</strong></h".$hashs.">";
}
回答1:
First a comment:
Normally, if you call a callback function within an OOP context you have to use
array(&$this, 'callback_function')
No, normally (these days) it's array($this, 'callback_function')
- without the &
.
Then, instead of $this
you can put any variable that's representing an object:
$obj = $this;
$callback = array($obj, 'method');
or
class That
{
function method() {...}
}
$obj = new That;
$callback = array($obj, 'method');
This just works, see the documentation of the callback pseudo type in the PHP Manual.
More similar to the code fragments of your question:
class Callback
{
function __construct()
{
$this->list = array("num" => 0, "dot" => 0, "normal" => 0);
$this->td = array("strike" => false, "bold" => false, "italic" => false, "underline" => false, "code" => false);
}
public function callback_heading($parameter)
{
$hashs = min(6, 1+strlen($parameter[1]));
return sprintf("<h%d><span class=\'indented\'>%s</span><strong>%s</strong></h%d>", $hashs, parameter[1], $parameter[2], $hashs);
}
}
class Basic
{
/** @var Callback */
private $cb;
function __construct()
{
// some other vars here
$obj = new Callback();
$this->cb = array($obj, 'callback_heading');
}
function replace($subject)
{
...
$result = preg_replace_callback($pattern, $this->cb, $subject);
}
}
$basic = new Basic;
$string = '123, test.';
$replaced = $basic->replace($string);
回答2:
Say your external class looks like this
<?php
class ExternalClass {
function callback() {
// do something here
}
}
If your callback function makes no reference to $this, you can call it statically like so:
preg_replace_callback($pattern, 'ExternalClass::callback', $subject);
Otherwise, your method should work in theory.
preg_replace_callback($pattern, array(new ExternalClass, 'callback'), $subject);
Read more about callbacks
来源:https://stackoverflow.com/questions/7894590/using-preg-replace-callback-with-external-class