问题
echo xx y11y rrr | awk '{ if ($2 ~/y[1-5]{2}y/) print $3}'
Why I cannot get any output?
Thank you.
回答1:
You need to enable "interval expressions" in regular expression matching by specifying either the --posix
or --re-interval
option.
e.g.
echo xx y11y rrr | awk --re-interval '{ if ($2 ~ /y[1-5]{2}y/) print $3}
From the man page:
--re-interval Enable the use of interval expressions in regular expression matching (see Regular Expressions, below). Interval expressions were not traditionally available in the AWK language. The POSIX standard added them, to make awk and egrep consistent with each other. However, their use is likely to break old AWK programs, so gawk only provides them if they are requested with this option, or when --posix is specified.
回答2:
You should force POSIX to use {} in awk
echo xx y11y rrr | awk -W posix '{ if ($2 ~/y[1-5]{2}y/) print $3}'
回答3:
On my machine:
$ echo xx y11y rrr | awk '{ if ($2 ~/y[1-5]{2}y/) print $3}'
rrr
Was this what you wanted? I'm using GNU awk 4.0.0 in Cygwin on Windows XP.
来源:https://stackoverflow.com/questions/8343058/simple-trouble-with-awk-and-regex