问题
This code works fine in Java 1.6:
public static String padLeft(String s, int n)
{
if (n <= 0)
return s;
int noOfSpaces = n * 2;
String output;
noOfSpaces = s.length() + noOfSpaces;
output = String.format("%1$#" + noOfSpaces + "s", s);
return output;
}
But newer versions (and some other VM implementations) throw this Exception
:
java.util.FormatFlagsConversionMismatchException: Mismatched Convertor =s, Flags= #
at java.util.Formatter$Transformer.transformFromString(Formatter.java:1020)
at java.util.Formatter$Transformer.transform(Formatter.java:861)
at java.util.Formatter.format(Formatter.java:565)
at java.util.Formatter.format(Formatter.java:509)
at java.lang.String.format(String.java:1961)
Any workarounds?
回答1:
You asked for a workaround; just use StringBuilder:
public static String padLeft(String s, int n) {
if (n <= 0)
return s;
int noOfSpaces = n * 2;
StringBuilder output = new StringBuilder(s.length() + noOfSpaces);
while (noOfSpaces > 0) {
output.append(" ");
noOfSpaces--;
}
output.append(s);
return output.toString();
}
回答2:
Since you are using #
flag in format string, you should pass Formattable as an argument (doc).
Any work arounds?
Don't use #
in format string?
来源:https://stackoverflow.com/questions/12420537/string-format-throws-formatflagsconversionmismatchexception