问题
Sander Steffann mentioned in a previous question of mine:
Addresses like 0000:0000:0000:0000:0000:0000:192.168.0.1 are written as 0000:0000:0000:0000:0000:0000:c0a8:0001 which is exactly the same address but in hex notation.
How do I detect in PHP if an address was written like eg.: ::0000:192.168.0.1
or 0000::0000:192.168.0.1
or 0000:0000:0000:0000:0000:0000:192.168.0.1
etc.? Is it enough to check if an IP-based string has '.' AND ':' ?
And how do I change this to the full string 0000:0000:0000:0000:0000:0000:c0a8:0001
?
Am I correct, to change this to IPv4 will be something like:
<?php
$strIP = '0000:0000:0000:0000:0000:0000:192.168.0.1';
$strResult = substr($strIP, strrpos($strIP, ':'));
echo $strResult; //192.168.0.1 ?
?>
... or are correct IP string representations more complex than what this snippet could do?
回答1:
First of all: why would you care how the address is written? inet_pton() will parse all variations for you and give you a consistent result, which you can then transform into binary, hex, or whatever you want.
All the code for converting things like ::192.168.0.1
to 0000:0000:0000:0000:0000:0000:c0a8:0001
was actually in my post. That's exactly what my example function does.
If you feed 0000:0000:0000:0000:0000:0000:192.168.0.1
to inet_pton() and then to inet_ntop() you'll get the canonical IPv6 notation, which is ::192.168.0.1
in this case. If that string begins with ::
and the rest contains no :
and three dots then you can be pretty sure it's an IPv4 address ;-)
To combine the answer to your previous question with this question:
function expand_ip_address($addr_str) {
/* First convert to binary, which also does syntax checking */
$addr_bin = @inet_pton($addr_str);
if ($addr_bin === FALSE) {
return FALSE;
}
$addr_hex = bin2hex($addr_bin);
/* See if this is an IPv4-Compatible IPv6 address (deprecated) or an
IPv4-Mapped IPv6 Address (used when IPv4 connections are mapped to
an IPv6 sockets and convert it to a normal IPv4 address */
if (strlen($addr_bin) == 16
&& substr($addr_hex, 0, 20) == str_repeat('0', 20)) {
/* First 80 bits are zero: now see if bits 81-96 are either all 0 or all 1 */
if (substr($addr_hex, 20, 4) == '0000')
|| substr($addr_hex, 20, 4) == 'ffff')) {
/* Remove leading bits so only the IPv4 bits remain */
$addr_bin = substr($addr_hex, 12);
}
}
/* Then differentiate between IPv4 and IPv6 */
if (strlen($addr_bin) == 4) {
/* IPv4: print each byte as 3 digits and add dots between them */
$ipv4_bytes = str_split($addr_bin);
$ipv4_ints = array_map('ord', $ipv4_bytes);
return vsprintf('%03d.%03d.%03d.%03d', $ipv4_ints);
} else {
/* IPv6: print as hex and add colons between each group of 4 hex digits */
return implode(':', str_split($addr_hex, 4));
}
}
回答2:
Your best bet is to not do this manually, but instead call inet_pton to get a binary representation, and then convert that to the format you wish to have.
$foo = inet_pton("::1");
for ($i = 0 ; $i < 8 ; $i++)
$arr[$i] = sprintf("%02x%02x", ord($foo[$i * 2]), ord($foo[$i * 2 + 1]));
$addr = implode(":", $arr);
回答3:
I can't believe I wrote this all out in one go and it worked the first time.
$strIP = '0000:0000:0000:0000:0000:0000:192.168.0.1';
$arrIP = explode(':', $strIP);
if( preg_match('/^\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}$/', $arrIP[count($arrIP)-1]) ) {
$ip4parts = explode('.', $arrIP[count($arrIP)-1]);
$ip6trans = sprintf("%02x%02x:%02x%02x", $ip4parts[0], $ip4parts[1], $ip4parts[2], $ip4parts[3]);
$arrIP[count($arrIP)-1] = $ip6trans;
$strIP = implode(':', $arrIP);
}
echo $strIP; //output: 0000:0000:0000:0000:0000:0000:c0a8:0001
Basically:
- Explode the string on
:
- Check if the last quad is formatted like an IP4 address
- Explode the last quad on
.
- Re-print the IP4 octets into two hex quads
- Replace the IP4 quad with the new ones
- Implode the array on
:
.
来源:https://stackoverflow.com/questions/14445582/change-ipv4-to-ipv6-string