问题
I have a dataset that looks something like this:
df <- structure(list(Claim.Num = c(500L, 500L, 600L, 600L, 700L, 700L,
100L, 200L, 300L), Amount = c(NA, 1000L, NA, 564L, 0L, 200L,
NA, 0L, NA), Company = structure(c(NA, 1L, NA, 4L, 2L, 3L, NA,
3L, NA), .Label = c("ATT", "Boeing", "Petco", "T Mobile"), class = "factor")), .Names =
c("Claim.Num", "Amount", "Company"), class = "data.frame", row.names = c(NA,
-9L))
I want to remove duplicate rows based on Claim Num values, but to remove duplicates based on the following criteria: df$Company == 'NA' | df$Amount == 0
In other words, remove records 1, 3, and 5.
I've gotten this far: df <- df[!duplicated(df$Claim.Num[which(df$Amount = 0 | df$Company == 'NA')]),]
The code runs without errors, but doesn't actually remove duplicate rows based on the required criteria. I think that's because I'm telling it to remove any duplicate Claim Nums which match to those criteria, but not to remove any duplicate Claim.Num
but treat certain Amounts & Companies preferentially for removal. Please note that, I can't simple filter out the dataset based on specified values, as there are other records that may have 0 or NA values, that require inclusion (e.g. records 8 & 9 shouldn't be excluded because their Claim.Nums are not duplicated).
回答1:
If you order your data frame first, then you can make sure duplicated
keeps the ones you want:
df.tmp <- with(df, df[order(ifelse(is.na(Company) | Amount == 0, 1, 0)), ])
df.tmp[!duplicated(df.tmp$Claim.Num), ]
# Claim.Num Amount Company
# 2 500 1000 ATT
# 4 600 564 T Mobile
# 6 700 200 Petco
# 7 100 NA <NA>
# 8 200 0 Petco
# 9 300 NA <NA>
回答2:
Slightly different approach
r <- merge(df,
aggregate(df$Amount,by=list(Claim.Num=df$Claim.Num),length),
by="Claim.Num")
result <-r[!(r$x>1 & (is.na(r$Company) | (r$Amount==0))),-ncol(r)]
result
# Claim.Num Amount Company
# 1 100 NA <NA>
# 2 200 0 Petco
# 3 300 NA <NA>
# 5 500 1000 ATT
# 7 600 564 T Mobile
# 9 700 200 Petco
This adds a column x
to indicate which rows have Claim.Num
present more than once, then filters the result based on your criteria. The use of -ncol(r)
just removes the column x
at the end.
回答3:
Another way based on subset
and logical indices:
subset(dat, !(duplicated(Claim.Num) | duplicated(Claim.Num, fromLast = TRUE)) |
(!is.na(Amount) & Amount))
Claim.Num Amount Company
2 500 1000 ATT
4 600 564 T Mobile
6 700 200 Petco
7 100 NA <NA>
8 200 0 Petco
9 300 NA <NA>
来源:https://stackoverflow.com/questions/21788378/remove-duplicates-based-on-specific-criteria