问题
What's the best way to get an url minus its query string in Objective-C? An example:
Input:
http://www.example.com/folder/page.htm?param1=value1¶m2=value2
Output:
http://www.example.com/folder/page.htm
Is there a NSURL method to do this that I'm missing?
回答1:
There's no NSURL method I can see. You might try something like:
NSURL *newURL = [[NSURL alloc] initWithScheme:[url scheme]
host:[url host]
path:[url path]];
Testing looks good:
#import <Foundation/Foundation.h>
int main(int argc, char *argv[]) {
NSAutoreleasePool *arp = [[NSAutoreleasePool alloc] init];
NSURL *url = [NSURL URLWithString:@"http://www.abc.com/foo/bar.cgi?a=1&b=2"];
NSURL *newURL = [[[NSURL alloc] initWithScheme:[url scheme]
host:[url host]
path:[url path]] autorelease];
NSLog(@"\n%@ --> %@", url, newURL);
[arp release];
return 0;
}
Running this produces:
$ gcc -lobjc -framework Foundation -std=c99 test.m ; ./a.out
2010-11-25 09:20:32.189 a.out[36068:903]
http://www.abc.com/foo/bar.cgi?a=1&b=2 --> http://www.abc.com/foo/bar.cgi
回答2:
Since iOS 8/OS X 10.9, there is an easier way to do this with NSURLComponents.
NSURL *url = [NSURL URLWithString:@"http://hostname.com/path?key=value"];
NSURLComponents *urlComponents = [[NSURLComponents alloc] initWithURL:url resolvingAgainstBaseURL:NO];
urlComponents.query = nil; // Strip out query parameters.
NSLog(@"Result: %@", urlComponents.string); // Should print http://hostname.com/path
回答3:
Here is the Swift version of Andree's answer, with some extra flavour -
extension NSURL {
func absoluteStringByTrimmingQuery() -> String? {
if var urlcomponents = NSURLComponents(URL: self, resolvingAgainstBaseURL: false) {
urlcomponents.query = nil
return urlcomponents.string
}
return nil
}
}
You can call it like -
let urlMinusQueryString = url.absoluteStringByTrimmingQuery()
回答4:
What you probably need is a combination of url's host and path components:
NSString *result = [[url host] stringByAppendingPathComponent:[url path]];
回答5:
You could try using query of NSURL to get the parameters, then strip that value using stringByReplacingOccurrencesOfString of NSString?
NSURL *before = [NSURL URLWithString:@"http://www.example.com/folder/page.htm?param1=value1¶m2=value2"];
NSString *after = [before.absoluteString stringByReplacingOccurrencesOfString:before.query withString:@""];
Note, the final URL will still end with ?, but you could easily strip that as well if needed.
回答6:
Swift Version
extension URL {
func absoluteStringByTrimmingQuery() -> String? {
if var urlcomponents = URLComponents(url: self, resolvingAgainstBaseURL: false) {
urlcomponents.query = nil
return urlcomponents.string
}
return nil
}
}
Hope this helps!
回答7:
NSURL has a query property which contains everything after the ? in a GET url. So simply subtract that from the end of the absoluteString, and you've got the url without the query.
NSURL *originalURL = [NSURL URLWithString:@"https://winker@127.0.0.1:1000/file/path/?q=dogfood"];
NSString *strippedString = [originalURL absoluteString];
NSUInteger queryLength = [[originalURL query] length];
strippedString = (queryLength ? [strippedString substringToIndex:[strippedString length] - (queryLength + 1)] : strippedString);
NSLog(@"Output: %@", strippedString);
Logs:
Output: https://winker@127.0.0.1:1000/file/path/
The +1 is for the ? which is not part of query.
回答8:
I think -baseURL might do what you want.
If not, you can can do a round trip through NSString like so:
NSString *string = [myURL absoluteString];
NSString base = [[string componentsSeparatedByString:@"?"] objectAtIndex:0];
NSURL *trimmed = [NSURL URLWithString:base];
回答9:
You might fancy the method replaceOccurrencesOfString:withString:options:range: of the NSMutableString class. I solved this by writing a category for NSURL:
#import <Foundation/Foundation.h>
@interface NSURL (StripQuery)
// Returns a new URL with the query stripped out.
// Note: If there is no query, returns a copy of this URL.
- (NSURL *)URLByStrippingQuery;
@end
@implementation NSURL (StripQuery)
- (NSURL *)URLByStrippingQuery
{
NSString *query = [self query];
// Simply copy if there was no query. (query is nil if URL has no '?',
// and equal to @"" if it has a '?' but no query after.)
if (!query || ![query length]) {
return [self copy];
}
NSMutableString *urlString = [NSMutableString stringWithString:[self absoluteString]];
[urlString replaceOccurrencesOfString:query
withString:@""
options:NSBackwardsSearch
range:NSMakeRange(0, [urlString length])];
return [NSURL URLWithString:urlString];
}
@end
This way, I can send this message to existing NSURL objects and have a new NSURL object be returned to me.
I tested it using this code:
int main(int argc, const char * argv[])
{
@autoreleasepool {
NSURL *url = [NSURL URLWithString:@"http://www.example.com/script.php?key1=val1&key2=val2"];
// NSURL *url = [NSURL URLWithString:@"http://www.example.com/script.php?"];
// NSURL *url = [NSURL URLWithString:@"http://www.example.com/script.php"];
NSURL *newURL = [url URLByStrippingQuery];
NSLog(@"Original URL: \"%@\"\n", [url absoluteString]);
NSLog(@"Stripped URL: \"%@\"\n", [newURL absoluteString]);
}
return 0;
}
and I got the following output (minus the time stamps):
Original URL: "http://www.example.com/script.php?key1=val1&key2=val2"
Stripped URL: "http://www.example.com/script.php?"
Note that the question mark ('?') still remains. I will leave it up to the reader to remove it in a secure way.
回答10:
We should try to use NSURLComponents
NSURL *url = @"http://example.com/test";
NSURLComponents *comps = [[NSURLComponents alloc] initWithURL:url resolvingAgainstBaseURL:YES];
NSString *cleanUrl = [NSString stringWithFormat:@"%@://%@",comps.scheme,comps.host];
if(comps.path.length > 0){
cleanUrl = [NSString stringWithFormat:@"%@/%@",cleanUrl,comps.path];
}
回答11:
I think what you're looking for is baseUrl.
来源：https://stackoverflow.com/questions/4271916/url-minus-query-string-in-objective-c