How to use execv() without warnings?

问题

I am working on MacOS-X Lion with GCC 4.2. This code works, but I get a warning I would like fix:

#include <unistd.h>
main()
{
    char *args[] = {"/bin/ls", "-r", "-t", "-l", (char *) 0 };
    execv("/bin/ls", args);
}

warning: deprecated conversion from string constant to 'char*'

I do not want the warning to be suppressed, I want not to have it at all. It is C++ code, not C.

Using a char *const (so exactly the type required by execv()) still produces the warning.

Thank you.

回答1:

This seems to be ok:

#include <unistd.h>
main()
{
    char const *args[] = {"/bin/ls", "-r", "-t", "-l", NULL };
    execv("/bin/ls", const_cast<char**>(args));
}

回答2:

You are converting a string constant to a mutable character pointer, change using an implicit cast, the compiler is warning you that newer versions of the language will not allow this cast.

When defining a string litteral c++ understands it to mean a constant character array you have defined it as a mutable character array, change your code accordingly.

回答3:

Change:

char *args[] = {"/bin/ls", "-r", "-t", "-l", (char *) 0 };

To:

char *const args[] = {"/bin/ls", "-r", "-t", "-l", NULL };

回答4:

The only reason you get the warning is that you're using g++, not gcc. In pure C, you'd get absolutely no warnings. It's actually quite difficult to create warning-free C++ code from this. To be honest, I tried but did not succeed.

These hurdles are one of the reasons for the existence of a certain philosophical school. See more here.

回答5:

I do not know why the accepted answer was selected, it does not remove any warnings when I run this code....

I cannot confirm on your specific platform, but adding casts to each string constant has made the warnings go away for me.

#include <unistd.h>
main()
{
    char* const args[] = {(char*)"/bin/ls", (char*)"-r", (char*)"-t", (char*)"-l", (char*) 0 };
    execv("/bin/ls", args);
}

#include <unistd.h>
main()
{
    char *args[] = {(char*)"/bin/ls", (char*)"-r", (char*)"-t", (char*)"-l", (char*) 0 };
    execv("/bin/ls", args);
}

It may be overly verbose and annoying, but the warnings go away.

I'm running this on: g++ (Ubuntu 4.8.4-2ubuntu1~14.04) 4.8.4

回答6:

change

char *args[] = {"/bin/ls", "-r", "-t", "-l", (char *) 0 };

char args[] = {(char*)"/bin/ls", (char*)"-r", (char*)"-t", (char*)"-l", 0 };

for usability u may will make a simple convert method.

来源：https://stackoverflow.com/questions/10790719/how-to-use-execv-without-warnings

标签

c++

macos

g++

warnings

execv