How can I integrate Tkinter with Python log in screen?

社会主义新天地 提交于 2019-12-18 16:39:34

问题


I am using Tkinter to create a login screen here. At the moment, the "keep me logged in" button at the bottom is redundant and will remain so. What I want to do is use this code:

from tkinter import *

root = Tk()

label_1 = Label(root, text="Username")
label_2 = Label(root, text="Password")

entry_1 = Entry(root)
entry_2 = Entry(root)

label_1.grid(row=0, sticky=E)
label_2.grid(row=1, sticky=E)
entry_1.grid(row=0, column=1)
entry_2.grid(row=1, column=1)

checkbox = Checkbutton(root, text="Keep me logged in")
checkbox.grid(columnspan=2)

in conjunction with:

username = "john"
input("Username: ")
while not username:
    if username == "john":
        print("Welcome")
    else:
        print("User not found")


password = "password"
while not password:
    input("password: ")
    if password == "password":
        print("Logged in")
    else:
        print("Incorrect password")

However the logging in code does not work and then on top of that I do not know where to begin with integrating the two with each other. I am some what new to python and even more so to Tkinter but am desperate for this help!

Thanks in advance!


回答1:


I extended your example. I made a class that holds your login window.

from tkinter import *
import tkinter.messagebox as tm


class LoginFrame(Frame):
    def __init__(self, master):
        super().__init__(master)

        self.label_username = Label(self, text="Username")
        self.label_password = Label(self, text="Password")

        self.entry_username = Entry(self)
        self.entry_password = Entry(self, show="*")

        self.label_username.grid(row=0, sticky=E)
        self.label_password.grid(row=1, sticky=E)
        self.entry_username.grid(row=0, column=1)
        self.entry_password.grid(row=1, column=1)

        self.checkbox = Checkbutton(self, text="Keep me logged in")
        self.checkbox.grid(columnspan=2)

        self.logbtn = Button(self, text="Login", command=self._login_btn_clicked)
        self.logbtn.grid(columnspan=2)

        self.pack()

    def _login_btn_clicked(self):
        # print("Clicked")
        username = self.entry_username.get()
        password = self.entry_password.get()

        # print(username, password)

        if username == "john" and password == "password":
            tm.showinfo("Login info", "Welcome John")
        else:
            tm.showerror("Login error", "Incorrect username")


root = Tk()
lf = LoginFrame(root)
root.mainloop()

Sorry for not going over every single line what is happening there. I leave it to you to figure out. Its good exercise. But I will say that the most important is command = self._login_btn_clicked. This function will be executed when you click login button. In this function, you take the values of username and password, and check if they are correct. Also I did not attach any callbacks to the checkbox. But it would be similar to what is already done.

Edit: Edited as requested in the comments.




回答2:


You probably want a 'Login' button, right? If you make that, you can bind a function to run when it is clicked using button's the command argument. In the function that the button calls you can do the checks for the correct username and password. Do not use the while loops though, just check once each time the button is pressed and respond accordingly.



来源:https://stackoverflow.com/questions/28156719/how-can-i-integrate-tkinter-with-python-log-in-screen

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